CODEWITHSUNDEEP
regexqt4qregexp
daisy
daisy

Reputation: 23541

Why isn't the following regexp working?

I'm trying to replace \\u0061 and \u0061 to %u0061 with QRegExp,

So I did this,

QString a = "\\u0061";
qDebug() << a.replace(QRegExp("\\?\\u"), "%u");

Since the slash can appear either once or twice, so I used a ? to represen the first slash, but it ain't working, what's wrong about it?

EDIT

Thanks to Denomales, it should be \\\\u that represents \\u, and I'm using \\\\+u right now.

Upvotes: 1

Views: 403

Answers (1)

Ro Yo Mi
Ro Yo Mi

Reputation: 15010

Description

Per the QT qregex documentation , see the section on Characters and Abbreviations for Sets of Characters:

Note: The C++ compiler transforms backslashes in strings. To include a \ in a regexp, enter it twice, i.e. \\. To match the backslash character itself, enter it four times, i.e. \\\\.

Care to give this a try:

[\\\\]{1,2}(u)

enter image description here

I've entered 4 backslashes so the various language layers can escape the backslash correctly. Then nested it inside square brackets and required it to appear 1 to 2 times. Essentially this should find the single and double backslashes before the letter u. You could then just replace with %u as in your example.

In my example the u character is captured and should be returned as group 1 to be used later in your replacement.

Upvotes: 2

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