CODEWITHSUNDEEP
scalascala-2.10slick
expert
expert

Reputation: 30145

Can I build update query with variable fields without using plain SQL?

Can I build update query with variable number of fields without using plain SQL ?

For example update of single column is simple - I just yield it to create narrow query.

Query(RolesTable).filter((role: RolesTable.type) => role.id === role_id).map((role: RolesTable.type) => role.name).update(name)

But what if Role has 5 fields and I want to allow API client to send me fields he wants to update ? How would I construct such query ?

Upvotes: 1

Views: 698

Answers (1)

cmbaxter
cmbaxter

Reputation: 35463

The key here is to use the ~ operator when yielding the selected columns. Using the example model from the documentation:

case class User(id: Option[Int], first: String, last: String)
object UsersTable extends Table[User]("users") {
  def id = column[Int]("id", O.PrimaryKey, O.AutoInc)
  def first = column[String]("first")
  def last = column[String]("last")
  def * = id.? ~ first ~ last <> (User, User.unapply _)
}

A select based on your example would look like this:

val cols = Query(UsersTable).filter((user: UsersTable.type) => user.id === userId).map((user: UsersTable.type) => user.first ~ user.last)

And then the update call would be:

cols.update((newFirst,newLast))

Also, if you wanted, you could re-write your select as a for comprehension as it shortens it up a bit:

val cols = for(user <- UsersTable if (user.id === userId)) yield user.first ~ user.last
cols.update((newFirst,newLast))

Upvotes: 3

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