CODEWITHSUNDEEP
javastringsplitnumbersnumber-formatting
karthi
karthi

Reputation: 1099

How to split the string into string and integer in java?

I have the String a="abcd1234" and I want to split this into String b="abcd" and Int c=1234. This Split code should apply for all king of input like ab123456 and acff432 and so on. How to split this kind of Strings. Is it possible?

Upvotes: 16

Views: 100277

Answers (10)

510 VIGNESH U
510 VIGNESH U

Reputation: 1

public class MyClass {
public static void main(String args[]) {
  String a = "a1j2a3i4";
    int i;
    String str1="";
    String str2="";
    for(i = 0; i < a.length(); i++){
             char c = a.charAt(i);
                if( '0' <= c && c <= '9' )
                         str1=str1+c;
                if( 'a' <= c && c <= 'z' )
                         str2=str2+c;
       }
   System.out.println(str1);
   System.out.println(str2);
   }}

Upvotes: 0

user14838237
user14838237

Reputation:

You can add some delimiter characters ⦀ to each group of symbols, and then split the string around those delimiters:

public static void main(String[] args) {
    String[][] arr = {
            split("abcd1234", "\u2980"),
            split("ab123456", "\u2980"),
            split("acff432", "\u2980")};

    Arrays.stream(arr)
            .map(Arrays::toString)
            .forEach(System.out::println);
    // [abcd, 1234]
    // [ab, 123456]
    // [acff, 432]
}

private static String[] split(String str, String delimiter) {
    return str
            // add delimiter characters
            // to non-empty sequences
            // of numeric characters
            // and non-numeric characters
            .replaceAll("(\\d+|\\D+)", "$1" + delimiter)
            // split the string around
            // delimiter characters
            .split(delimiter, 0);
}

See also: How to split a string delimited on if substring can be casted as an int?

Upvotes: 0

Charlie Lomello
Charlie Lomello

Reputation: 67

try with this:

String input_string = "asdf1234";
String string_output=input_string.replaceAll("[^A-Za-z]", "");
int number_output=Integer.parseInt(input_string.replaceAll("[^0-9]", ""));
System.out.println("string_output = "+string_output);
System.out.println("number_output = "+number_output);

Upvotes: 0

Mohit Tyagi
Mohit Tyagi

Reputation: 2876

Use regex "[^A-Z0-9]+|(?<=[A-Z])(?=[0-9])|(?<=[0-9])(?=[A-Z])" to split the sting by alphabets and numbers.

for e.g.

String str = "ABC123DEF456";

Then the output by using this regex will be :

ABC
123
DEF
456

Upvotes: 0

chidanand
chidanand

Reputation: 17

String st = "abcd1234";
String st1=st.replaceAll("[^A-Za-z]", "");
String st2=st.replaceAll("[^0-9]", "");
System.out.println("String b = "+st1);
System.out.println("Int c = "+st2);

Output

String b = abcd
Int c = 1234

Upvotes: 1

sadhu
sadhu

Reputation: 1479

public static void main(String... s) throws Exception {
        Pattern VALID_PATTERN = Pattern.compile("([A-Za-z])+|[0-9]*");
    List<String> chunks = new ArrayList<String>();
    Matcher matcher = VALID_PATTERN.matcher("ab1458");
    while (matcher.find()) {
        chunks.add( matcher.group() );
    }
}

Upvotes: 0

SimonC
SimonC

Reputation: 6718

Use a regular expression:

Pattern p = Pattern.compile("([a-z]+)([0-9]+)");
Matcher m = p.matcher(string);
if (!m.find())
{ 
  // handle bad string
}
String s = m.group(1);
int i = Integer.parseInt(m.group(2));

I haven't compiled this, but you should get the idea.

Upvotes: 3

ConcurrentHashMap
ConcurrentHashMap

Reputation: 5084

You could try to split on a regular expression like (?<=\D)(?=\d). Try this one:

String str = "abcd1234";
String[] part = str.split("(?<=\\D)(?=\\d)");
System.out.println(part[0]);
System.out.println(part[1]);

will output

abcd
1234

You might parse the digit String to Integer with Integer.parseInt(part[1]).

Upvotes: 35

Javier Diaz
Javier Diaz

Reputation: 1830

You can do the next:

  1. Split by a regex like split("(?=\\d)(?<!\\d)")
  2. You have an array of strings with that and you only have to parse it.

Upvotes: 4

johnchen902
johnchen902

Reputation: 9601

A brute-force solution.

String a = "abcd1234";
int i;
for(i = 0; i < a.length(); i++){
    char c = a.charAt(i);
    if( '0' <= c && c <= '9' )
        break;
}
String alphaPart = a.substring(0, i);
String numberPart = a.substring(i);

Upvotes: 0

Related Questions