CODEWITHSUNDEEP
javadoublerounding
np98765
np98765

Reputation: 143

Rounding to the nearest half (NOT the nearest whole)

I need to round a double to the nearest .5. I do not want to end up with a number ending in .0.

I've searched around for a bit, but it seems like everyone wants to round to the nearest multiple of .5 rather than just the nearest half but not whole. I tried dividing by .5, rounding that, and multiplying by .5, but this still rounds to multiples of .5. Adding or subtracting .5 after this will not always round the number where it should go (you might add when you should have subtracted).

Any help would be greatly appreciated.

Upvotes: 14

Views: 10938

Answers (3)

MikeL
MikeL

Reputation: 5621

I think that Math.round(num * 2) / 2.0f should solve the rounding to the nearest half problem:

Math.round(3.9 * 2) / 2.0f == 8 / 2.0f = 4.0
Math.round(3.6 * 2) / 2.0f == 7 / 2.0f = 3.5
Math.round(3.1 * 2) / 2.0f == 6 / 2.0f = 3.0

Upvotes: 18

mauretto
mauretto

Reputation: 3212

Subtract, round and add...

Math.round(value - 0.5) + 0.5

Another working way mentioned in question's comments:

Math.floor(value) + 0.5

Upvotes: 9

sschrass
sschrass

Reputation: 7166

rounding to any fraction f:

double f = 0.5;
double rounded = f * Math.round(x/f);

Upvotes: 3

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