Reputation: 147
I am using given below code in XSL file Both xsl and Results.xml are at same location but it cant give output.actually i want to access nodes of Results.xml file to extract data.
<xsl:variable name="fi" select="document('Results.xml')"/>
<b><xsl:value-of select="$fi/Report/Doc/DName"/></b>
Upvotes: 1
Views: 7225
Reputation: 459
When the below XSLT
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"/>
<xsl:template match="/">
<xsl:variable name="fi" select="document('Results.xml')"/>
<b><xsl:value-of select="$fi/Report/Doc/DName"/></b>
</xsl:template>
</xsl:stylesheet>
transforms below XML
<?xml version='1.0'?>
<Report>
<Doc>
<DName>Sample</DName>
</Doc>
</Report>
gives the required output
<?xml version='1.0' ?>
<b>Sample</b>
Upvotes: 2