CODEWITHSUNDEEP
phpcheckboxecho
Ace
Ace

Reputation: 11

For loops & If Statements

I'm working on this code in PHP and basically I have 5 checkboxes, for 5 individual items, each called "ItemCheck" and they have values of 0-4. Now I wrote a code where it has it so it displays the numbers that are checked from those 5 check lists.

Form:

for ($i=0;$i<count(5);$i++){
echo "
<input type='checkbox' name='ItemCheck' value='$i.check'>$i</input><br>"}

PHP Process:

if (isset($_POST['ItemCheck'])){

    for ($o=0;$o<$ItemCount;$o++){

        if($_POST['ItemCheck'] == $o.'.check') {
            echo "Item " . $o . "<br>";

            }
    }
} 
else{ echo "You must select at least one product";}

Although say if I check box #1,2 & 3, the final output will only display "Item 3". Now matter how many checkboxes you select, it will only display the one with the highest value and none other. Does anybody know what's wrong with the code and how to have it so it displays each individual number that's selected, and not just the one with the highest value?

Upvotes: 1

Views: 95

Answers (1)

Orangepill
Orangepill

Reputation: 24645

What you want to do is set the name of the checkbox element ItemCheck[] this will make $_POST["ItemCheck"] an array.

Example:

for ($i=0;$i<count(5);$i++){
    echo "<input type='checkbox' name='ItemCheck[]' value='$i.check'/> $i<br>";
}

Another thing to note is the browser won't post up anything for an unchecked checkbox so I think your processor needs to be like this.

<?php
if (isset($_POST['ItemCheck'])){
    for ($o=0;$o<count($_POST['ItemCheck']);$o++){
            echo "Item " . $_POST['ItemCheck'] . "<br>";
    }
} else {
    echo "You must select at least one product";
}
?>

Another thing so make sure of is that your form has the method set to POST

Upvotes: 1

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