Reputation: 6948
Following code adds an asp.net webforms control to my content placeholder in webforms application:
var someControl = (System.Web.UI.UserControl)LoadControl("~/serverPath/" + ControlName + ".ascx");
phContentControls.Controls.Add(someControl);
So i'm wondering is there any way i can add rendered asp.net mvc view to my control?
omg, wtf i've just asked :D
Upvotes: 1
Views: 433
Reputation: 6121
You could try doing something like the following:
This is an MvcUtility Class I use when I would like to render PartialViews or ChildActions in a Webforms Page, I don't think I have used it in a UserControl however.
Not sure what MVC version you are using but I know this works with MVC 3 and Razor Views.
public static class MvcUtility
{
public static void RenderPartial(string partialViewName, object model)
{
// Get the HttpContext
HttpContextBase httpContextBase = new HttpContextWrapper(HttpContext.Current);
// Build the route data, pointing to the Some controller
RouteData routeData = new RouteData();
routeData.Values.Add("controller", typeof(Controller).Name);
// Create the controller context
ControllerContext controllerContext = new ControllerContext(new RequestContext(httpContextBase, routeData), new Controller());
// Find the partial view
IView view = FindPartialView(controllerContext, partialViewName);
// create the view context and pass in the model
ViewContext viewContext = new ViewContext(controllerContext, view, new ViewDataDictionary { Model = model }, new TempDataDictionary(), httpContextBase.Response.Output);
// finally, render the view
view.Render(viewContext, httpContextBase.Response.Output);
}
private static IView FindPartialView(ControllerContext controllerContext, string partialViewName)
{
// try to find the partial view
ViewEngineResult result = ViewEngines.Engines.FindPartialView(controllerContext, partialViewName);
if (result.View != null)
{
return result.View;
}
// wasn't found - construct error message
StringBuilder locationsText = new StringBuilder();
foreach (string location in result.SearchedLocations)
{
locationsText.AppendLine();
locationsText.Append(location);
}
throw new InvalidOperationException(String.Format("Partial view {0} not found. Locations Searched: {1}", partialViewName, locationsText));
}
public static void RenderAction(string controllerName, string actionName, object routeValues)
{
RenderPartial("RenderActionUtil", new RenderActionVM() { ControllerName = controllerName, ActionName = actionName, RouteValues = routeValues });
}
}
To render a ChildAction you will need a partial view in the Shared MVC Views Folder:
@model YourNamespace.RenderActionVM
@{
Html.RenderAction(Model.ActionName, Model.ControllerName, Model.RouteValues);
}
And the View Model:
public class RenderActionVM
{
public string ControllerName { get; set; }
public string ActionName { get; set; }
public object RouteValues { get; set; }
}
And finally in your webforms page call like this:
<% MvcUtility.RenderPartial("_SomePartial", null); %>
<% MvcUtility.RenderAction("SomeController", "SomeAction", new { accountID = Request.QueryString["id"], dateTime = DateTime.Now }); %>
Upvotes: 1