CODEWITHSUNDEEP
javascript
LIXer
LIXer

Reputation: 362

What does the 'in' keyword in javascript mean?

I found this code:

if (!("aa" in window)) {  
    alert('oh my god');
    var aa = 1;  
}  
alert("aa" in window);
alert(aa);

This code the second alert is alert true,but,the third alert is 'undefined',and the alert in the 'if' is not run. Why?

I think the reason is the in; what is its effect?

I searched on Google, but found nothing, because Google thinks the word ‘in&srquo; is a filter word.

We always use the in in loops, but, frankly speaking, I use it but don’t really understand it.

Upvotes: 9

Views: 7310

Answers (3)

mohan mu
mohan mu

Reputation: 83

in checks if property exists in Object

// in the below snippet they are checking if 'aa' property exists in 'window' Object . Since variables are function declarations are hoisted. you'll never enter inside if block .

var aa = undefined ;
if (!("aa" in window)) {   //2 => 'aa' property exists 
    alert('oh my god');  
    aa = 1;         // 1 =>  hoisted 
}

Upvotes: 1

Denys Séguret
Denys Séguret

Reputation: 382130

This tests if the window object has a property (filled or not) whose key is "aa".

This operator is very useful because it works even if the value is undefined :

window.aa = undefined; // or just aa=undefined if you're in the global scope
console.log('aa' in window); // logs true

It also works if the property isn't enumerable :

console.log('length' in []); // logs true

In your case, there may not be an aa value, but if the alert shows you true, the property was added to window.

MDN reference on in

Note that the for...in statement is different in that it doesn't really use the in operator but is a specific construct.

MDN reference on for...in

EDIT : an explanation of your edited question (very different from the first one) :

Your confusion seems to arise from the fact you declared the var aa = 1; in a block. You should know that the scope of a variable in JavaScript is either a function of the global scope and that declarations are hoisted. So your code is in fact equivalent to 

var aa = undefined;
if (!("aa" in window)) { // aa is in window, so we don't enter here
    alert('oh my god');
    aa = 1;  
}  
alert("aa" in window); // yes, the property exists, it's true
alert(aa); // aa is still undefined

Upvotes: 17

andyb
andyb

Reputation: 43823

Taking the alerts in order:

  • alert #1 is never reached because ("aa" in window) === true so the if boolean condition is false.

JavaScript has function scope and the variable aa is "hoisted" up to the top of the scope first, so it is defined.

  • alert #2

"aa" in window is true because the variable was added to the window object when it was hoisted up. Equivalent to just writing:

var foo;
"foo" in window (which === true)
  • alert #3

From the Standard ECMA-262 ECMAScript Language Specification :

A variable statement declares variables that are created as defined in 10.5. Variables are initialised to undefined when created. A variable with an Initialiser is assigned the value of its AssignmentExpression when the VariableStatement is executed, not when the variable is created.

So aa is undefined since the assignment was never executed.

Upvotes: 2

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