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pythonloopssetattr
Mattia
Mattia

Reputation: 47

Python: avoid __setattr__ loop using __dict__, shouldn't it loop anyway?

I know that you should be aware while redefine setattr method that you could end in a loop.

I know there's two solution to avoid loops:

1) using object superclass, calling :

object.__setattr__(instance,attr,value)

2) using the class dict:

self.__dict__[attr] = value

My question is, shouldn't the __dict__ solution end up in a loop too? and why it isn't?

Is because that way we're calling the __setattr__ of the __dict__ object (everything is an object) or what?

And if so, shouldn't it work the same for everything?

Upvotes: 0

Views: 976

Answers (1)

mgilson
mgilson

Reputation: 310227

Why would you expect it to end up in a loop?

instance.__dict__[attr] = value is basically what object.__setattr__(instance,attr,value) does (for normal attributes). Note that __dict__[attr] = whatever does not call __setattr__ at all. It calls __setitem__ which is a different method entirely.

Upvotes: 5

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