CODEWITHSUNDEEP
perlunix
Jake Smith
Jake Smith

Reputation: 7

argument escaping from command line (perl)

I'm a perl noob here and was wanting to run this from the command line of my unix machine.

./myprog.pl $str1 str2

Where I need to replace str2 with str1. Trouble is that I don't know how to escape from the $ in the str1 argument. I tried looking on here and on other websites but I couldnt find anything. Any help would be greatly appreciated!

Upvotes: 1

Views: 301

Answers (1)

ikegami
ikegami

Reputation: 386706

What shell? Is that the bourne-shell or a derivative, then both of the following will pass $str1 and str2 to the program.

./myprog.pl '$str1' str2

./myprog.pl \$str1 str2

But you talk of "replacing". Is the first arg suppose to be a regex pattern that matches $str1? If so, then you can use either of the following:

./myprog.pl '\$str1' str2

./myprog.pl \\\$str1 str2

This escapes $ for the regex engine (by adding a \), then escapes the \ and $ for the shell (by adding quotes or extra \s).

Upvotes: 1

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