Reputation: 159
I'm trying to use T-SQL LIKE against multiple values. After my research, the easiest way seems to be something similar to:
SELECT Column1
FROM Table_1
WHERE Column1 LIKE '[A,B,C]%'
So that I can expect the output looks like A1,B2,C3...
My problem is that the elements(A,B,C) for my scenario are in the format of "X/Y/Z"—yes, it contains slashes! And slash will be treated as a delimiter—the same as comma. For instance, I want to select any places in New York, Tokyo and London, so I wrote:
WHERE Location LIKE '[US/New York, Japan/Tokyo, UK/London]%'
But it does the same as
WHERE Location LIKE '[US,New York, Japan, Tokyo, UK, London]%'
And it will return US/LA/CBD or Tokyo/Tower...
How can I escape slash within the square brackets for the LIKE clause here?
Here is the sample table:
DECLARE @temp TABLE (Location NVARCHAR(50))
INSERT INTO @temp (Location ) VALUES ('US/New York/A')
INSERT INTO @temp (Location ) VALUES('New York/B')
INSERT INTO @temp (Location ) VALUES ('Japan/Tokyo/C')
INSERT INTO @temp (Location ) VALUES ('Tokyo/D')
INSERT INTO @temp (Location ) VALUES ('UK/London/E')
INSERT INTO @temp (Location ) VALUES('London/F')
And below is my draft script:
SELECT *
FROM @temp
WHERE Location LIKE '[US/New York, Japan/Tokyo, UK/London]%'
I was expecting the output is:
US/New York/A
Japan/Tokyo/C
UK/London/E
But actually all of them will be pulled out.
Upvotes: 7
Views: 44346
Reputation: 64674
DECLARE @temp TABLE ( Location NVARCHAR(50) )
INSERT @temp (Location )
VALUES ('US/New York/A')
, ('New York/B')
, ('Japan/Tokyo/A')
, ('Tokyo/B')
, ('UK/London/A')
, ('London/B')
Select *
From @temp
Where Location Like '%/A'
There is no need to escape the /
in this case. You can simply use an expression with a trailing wildcard.
It appears you may have a misconception about how the []
pattern is interpreted in the LIKE function. When you have a pattern like '[US/New York]%'
, it is saying "Find values that start with any of the following characters U
,S
,/
,N
,e
,w
, (space), Y
, o
,r
, or k
. Thus, such a pattern would find a value South Africa
or Outer Mongolia
. It isn't looking for rows where the entire value is equal to US/New York
.
One way to achieve what you seek is it to use multiple Or
statements:
Select *
From @temp
Where Location Like 'US/New York%'
Or Location Like 'Japan/Tokyo%'
Or Location Like 'UK/London%'
Upvotes: 1
Reputation: 981
Try separating the path separators from the valid character ranges.
WHERE name LIKE '%[/][A-Z][/][A-Z]_'
This would match strings like blabla/A/A1 and xxx/B/B1
The brackets are treated like 'a collection of allowed characters'. Based on your rephrased question, I think you could get by by simply combining some of the wildcard characters with some literal values. Here are some samples:
Ending with slash B:
SELECT *
FROM @temp
WHERE Location LIKE '%/B'
Ending in slash 'any single character'
SELECT *
FROM @temp
WHERE Location LIKE '%/_'
Starting with London—any number of chars—ending in slash 'any single character'
SELECT *
FROM @temp
WHERE Location LIKE 'London%/_'
-- having London anywhere, ending with in slash 'any single character'
SELECT *
FROM @temp
WHERE Location LIKE '%London%/_'
Upvotes: 0
Reputation: 122042
Try this one -
DECLARE @temp TABLE (name NVARCHAR(50))
INSERT INTO @temp (name)
VALUES ('Ben S'), ('test')
SELECT DISTINCT t.*
FROM @temp t
CROSS JOIN (
SELECT *
FROM (VALUES ('A'), ('B'), ('C')) t(t2)
) t2
WHERE t.name LIKE '%' + t2 + '%'
Or try this -
SELECT t.*
FROM @temp t
WHERE EXISTS(
SELECT 1
FROM (VALUES ('A'), ('B'), ('C')) c(t2)
WHERE t.name LIKE '%' + t2 + '%'
)
Upvotes: 0
Reputation: 140
declare @str nvarchar(10);
set @str='X/Y/Z';
SELECT name FROM dbo.Slash WHERE name LIKE @str+'%'
It will retrieve X/Y/Z1,X/Y/Z,..
Upvotes: 0