CODEWITHSUNDEEP
pythonpandasdatetime-series
user7289
user7289

Reputation: 34328

How to convert Pandas Series of dates string into date objects?

I have a Pandas data frame and one of the columns, have dates in string format of YYYY-MM-DD.

For e.g. : '2013-10-28'

At the moment the dtype of the column is object.

How do I convert the column values to Pandas date format?

Upvotes: 154

Views: 393323

Answers (11)

fantabolous
fantabolous

Reputation: 22716

I imagine a lot of data comes into Pandas from CSV files, in which case you can simply convert the date during the initial CSV read:

dfcsv = pd.read_csv('xyz.csv', parse_dates=[0]) where the 0 refers to the column the date is in.
You could also add , index_col=0 in there if you want the date to be your index.

See https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.read_csv.html

You can also select column(s) to parse by name rather than position, e.g. parse_dates=['thedate']

Upvotes: 47

shubham maini
shubham maini

Reputation: 19

You can use the pandas.to_datetime()

Upvotes: -1

Andy Hayden
Andy Hayden

Reputation: 375485

Essentially equivalent to @waitingkuo, but I would use pd.to_datetime here (it seems a little cleaner, and offers some additional functionality e.g. dayfirst):

In [11]: df
Out[11]:
   a        time
0  1  2013-01-01
1  2  2013-01-02
2  3  2013-01-03

In [12]: pd.to_datetime(df['time'])
Out[12]:
0   2013-01-01 00:00:00
1   2013-01-02 00:00:00
2   2013-01-03 00:00:00
Name: time, dtype: datetime64[ns]

In [13]: df['time'] = pd.to_datetime(df['time'])

In [14]: df
Out[14]:
   a                time
0  1 2013-01-01 00:00:00
1  2 2013-01-02 00:00:00
2  3 2013-01-03 00:00:00

Handling ValueErrors
If you run into a situation where doing

df['time'] = pd.to_datetime(df['time'])

Throws a

ValueError: Unknown string format

That means you have invalid (non-coercible) values. If you are okay with having them converted to pd.NaT, you can add an errors='coerce' argument to to_datetime:

df['time'] = pd.to_datetime(df['time'], errors='coerce')

Upvotes: 160

rubebop
rubebop

Reputation: 476

For the sake of completeness, another option, which might not be the most straightforward one, a bit similar to the one proposed by @SSS, but using rather the datetime library is:

import datetime
df["Date"] = df["Date"].apply(lambda x: datetime.datetime.strptime(x, '%Y-%d-%m').date())

Upvotes: 1

donDrey
donDrey

Reputation: 41

 #   Column          Non-Null Count   Dtype         
---  ------          --------------   -----         
 0   startDay        110526 non-null  object
 1   endDay          110526 non-null  object

import pandas as pd

df['startDay'] = pd.to_datetime(df.startDay)

df['endDay'] = pd.to_datetime(df.endDay)

 #   Column          Non-Null Count   Dtype         
---  ------          --------------   -----         
 0   startDay        110526 non-null  datetime64[ns]
 1   endDay          110526 non-null  datetime64[ns]

Upvotes: 0

Mwanaidi Nicole
Mwanaidi Nicole

Reputation: 1

Try to convert one of the rows into timestamp using the pd.to_datetime function and then use .map to map the formular to the entire column

Upvotes: -1

David Valenzuela Urrutia
David Valenzuela Urrutia

Reputation: 738

If you want to get the DATE and not DATETIME format:

df["id_date"] = pd.to_datetime(df["id_date"]).dt.date

Upvotes: 12

SSS
SSS

Reputation: 300

Another way to do this and this works well if you have multiple columns to convert to datetime. 

cols = ['date1','date2']
df[cols] = df[cols].apply(pd.to_datetime)

Upvotes: 7

Ted M.
Ted M.

Reputation: 23

It may be the case that dates need to be converted to a different frequency. In this case, I would suggest setting an index by dates.

#set an index by dates
df.set_index(['time'], drop=True, inplace=True)

After this, you can more easily convert to the type of date format you will need most. Below, I sequentially convert to a number of date formats, ultimately ending up with a set of daily dates at the beginning of the month.

#Convert to daily dates
df.index = pd.DatetimeIndex(data=df.index)

#Convert to monthly dates
df.index = df.index.to_period(freq='M')

#Convert to strings
df.index = df.index.strftime('%Y-%m')

#Convert to daily dates
df.index = pd.DatetimeIndex(data=df.index)

For brevity, I don't show that I run the following code after each line above:

print(df.index)
print(df.index.dtype)
print(type(df.index))

This gives me the following output:

Index(['2013-01-01', '2013-01-02', '2013-01-03'], dtype='object', name='time')
object
<class 'pandas.core.indexes.base.Index'>

DatetimeIndex(['2013-01-01', '2013-01-02', '2013-01-03'], dtype='datetime64[ns]', name='time', freq=None)
datetime64[ns]
<class 'pandas.core.indexes.datetimes.DatetimeIndex'>

PeriodIndex(['2013-01', '2013-01', '2013-01'], dtype='period[M]', name='time', freq='M')
period[M]
<class 'pandas.core.indexes.period.PeriodIndex'>

Index(['2013-01', '2013-01', '2013-01'], dtype='object')
object
<class 'pandas.core.indexes.base.Index'>

DatetimeIndex(['2013-01-01', '2013-01-01', '2013-01-01'], dtype='datetime64[ns]', freq=None)
datetime64[ns]
<class 'pandas.core.indexes.datetimes.DatetimeIndex'>

Upvotes: 2

szeitlin
szeitlin

Reputation: 3341

Now you can do df['column'].dt.date

Note that for datetime objects, if you don't see the hour when they're all 00:00:00, that's not pandas. That's iPython notebook trying to make things look pretty.

Upvotes: 30

waitingkuo
waitingkuo

Reputation: 93784

Use astype

In [31]: df
Out[31]: 
   a        time
0  1  2013-01-01
1  2  2013-01-02
2  3  2013-01-03

In [32]: df['time'] = df['time'].astype('datetime64[ns]')

In [33]: df
Out[33]: 
   a                time
0  1 2013-01-01 00:00:00
1  2 2013-01-02 00:00:00
2  3 2013-01-03 00:00:00

Upvotes: 138

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