AJJ
AJJ

Reputation: 897

many ID's one form

I am trying to display two sets of data from a table. I'm making a shop for my game, and have a database that lists the pokemon/price/type/id of the pokemon in the shop. Right now I have it almost working, it displays all the pokemon in the shop and they all have a buy button underneath them, but for some reason no matter what pokemon you try to buy it only buys the one on the top of the list. I hope I explained it well enough here is my code.

if ($_POST['A'] == '1' ) {
$token= mysql_real_escape_string($_POST['token']);
$tokenn = strip_tags($token);


$sql234 = "SELECT * FROM ticketshop";
$result2 = mysql_query("SELECT * FROM ticketshop");
while($row2 = mysql_fetch_array($result2)){


$sql23 = "SELECT * FROM users WHERE username='".$_SESSION['username']."')";
$result = mysql_query("SELECT * FROM users WHERE username='".$_SESSION['username']."'");
while($row = mysql_fetch_array($result)){
    echo "You have ".$row['ticket']." Tickets" ;
    echo "<p></p>" ;
if (isset($_POST['slot1'])) {
    if ($row['ticket'] >= $row2['price']) {
        echo "You have bought ".$row2['pokemon']."" ;
        mysql_query("UPDATE users SET ticket=ticket-".$row2['price']." WHERE username='".$_SESSION['username']."'") 
            or die(mysql_error());

        mysql_query("INSERT INTO user_pokemon 
(pokemon, belongsto, exp, time_stamp, slot, level, type) VALUES ('".$row2['pokemon']."','".$_SESSION['username']."', 100,'".time()."','0', '5', '".$row2['type']."' )") 
            or die(mysql_error());  
    } else {
        echo "You can't afford ".$row2['pokemon']."";
}
}
}
}

Upvotes: 0

Views: 78

Answers (1)

Fabio
Fabio

Reputation: 23500

You are getting the error because you are closing connection to database and after you try to fetch result from second query which ends up with the error

<?php } /* mysql_close($conn);*/ /*comment or remove closing connection*/ ?>

<p><b>Listing of pending applications</b></p>

Then I would like to remember you that mysql_ functions are deprecated so i would advise you to switch to mysqli or PDO.

Upvotes: 1

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