CODEWITHSUNDEEP
c++qtqt4cursorqwidget
Freedom_Ben
Freedom_Ben

Reputation: 11933

How to check current cursor shape in Qt

Qt 4.8 on Fedora 17 x64

In my QWidget::mouseMoveEvent, I am trying to check to see if the cursor is currently set to either Qt::SizeVerCursor or Qt::SizeHorCursor, but the QCursor returned by calling QWidget::cursor() cannot be compared to either Qt::SizeVerCursor or Qt::SizeHorCursor because of a compile error. It looks like this is because both Qt::SizeVerCursor and Qt::SizeHorCursor are actually Qt::CursorShape instead of QCursor.

This code fails to compile:

void MyGraphicsView::mouseMoveEvent( QMouseEvent *event )
{
    if( ( cursor() == Qt::SizeHorCursor ) || ( cursor() == Qt::SizeVerCursor ) )
    {
        qDebugGreen() << "Cursor is a size cursor!";
    }

    QGraphicsView::mouseMoveEvent( event );
}

Here is the compile error:

error: no match for ‘operator==’ in ‘QWidget::cursor() const() == (Qt::CursorShape)6u’

How can I check if the current cursor is either Qt::SizeVerCursor or Qt::SizeHorCursor?

Upvotes: 1

Views: 4217

Answers (1)

Petr Jirouš
Petr Jirouš

Reputation: 161

Imho cursor().shape() should work.

Upvotes: 7

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