Reputation: 51264
How can I get the last day of the month in PHP?
Given:
$a_date = "2009-11-23"
I want 2009-11-30; and given
$a_date = "2009-12-23"
I want 2009-12-31.
Upvotes: 503
Views: 713605
Reputation: 149
Here's a one liner that may be of interest.'Y-m-j' is the date format for the output and the second string is the date of interest with an offset string:
echo date('Y-m-j', strtotime('2009-12-23 last day of this month'));
Upvotes: 0
Reputation: 2398
If you're using a 32-bit system, then the strtotime() code will fail after the year 2038 due to the Year 2038 problem.
For example, on a 32-bit system, this code will echo 1970-01-31
:
$a_date = "2040-11-23";
echo date("Y-m-t", strtotime($a_date));
If you need your code to support 32-bit systems, then you should instead use the DateTime function:
$d = new DateTime('2040-11-23');
echo $d->format('Y-m-t');
That code will correctly output 2040-11-30
on both a 32-bit or 64-bit system.
Upvotes: 159
Reputation: 17906
The most elegant for me is using DateTime
I wonder I do not see DateTime::createFromFormat
, one-liner
$lastDay = \DateTime::createFromFormat("Y-m-d", "2009-11-23")->format("Y-m-t");
Upvotes: 31
Reputation: 4534
2 lines code and you are done:
$oDate = new DateTime("2019-11-23");
// now your date object has been updated with last day of month
$oDate->setDate($oDate->format("Y"),$oDate->format("m"),$oDate->format("t"));
// or to just echo you can skip the above line using this
echo $oDate->format("Y-m-t");
Upvotes: 3
Reputation: 63
if you want to go back few months you can do something like this as well.
$list = [
0, 1, 2, 3
];
$date = new \Datetime();
$dates = [];
foreach($list as $item)
{
$set = clone $date;
$set->modify("-$item month ");
$dates[] = $set->modify("last day of this month");
}
return $dates;
Upvotes: 2
Reputation: 89
I needed the last day of the next month, maybe someone will need it:
echo date("Y-m-t", strtotime("next month")); //is 2020-08-13, return 2020-09-30
Upvotes: -1
Reputation: 341
$startDate = '2011-12-01';
$endDate = date('Y-m');
while (true) {
try {
$startDateTime = new DateTime($startDate);
$startDateTime->add(new DateInterval('P1M'));
$startDate = $startDateTime->format('Y-m-d');
$endTime = $startDateTime->format('Y-m-t');
echo $startDate . ' => ' . $endTime . PHP_EOL;
if ($startDateTime->format('Y-m') == $endDate) {
break;
}
} catch (Exception $exception) {
var_dump($exception->getMessage());
break;
}
}
After testing many solutions, this works best for me.
Upvotes: 0
Reputation: 2643
Nowadays DateTime does this quite conveniently if you have month and year you can
$date = new DateTime('last day of '.$year.'-'.$month);
From another DateTime object that would be
$date = new DateTime('last day of '.$otherdate->format('Y-m'));
Upvotes: 9
Reputation: 490
I am using strtotime with cal_days_in_month as following:
$date_at_last_of_month=date('Y-m-d', strtotime('2020-4-1
+'.(cal_days_in_month(CAL_GREGORIAN,4,2020)-1).' day'));
Upvotes: 2
Reputation: 972
Carbon API extension for PHP DateTime
Carbon::parse("2009-11-23")->lastOfMonth()->day;
or
Carbon::createFromDate(2009, 11, 23)->lastOfMonth()->day;
will return
30
Upvotes: 5
Reputation: 1228
If you have a month wise get the last date of the month then,
public function getLastDateOfMonth($month)
{
$date = date('Y').'-'.$month.'-01'; //make date of month
return date('t', strtotime($date));
}
$this->getLastDateOfMonth(01); //31
Upvotes: 3
Reputation: 4767
You can find last day of the month several ways. But simply you can do this using PHP strtotime() and date() function.I'd imagine your final code would look something like this:
$a_date = "2009-11-23";
echo date('Y-m-t',strtotime($a_date));
But If you are using PHP >= 5.2 I strongly suggest you use the new DateTime object. For example like below:
$a_date = "2009-11-23";
$date = new DateTime($a_date);
$date->modify('last day of this month');
echo $date->format('Y-m-d');
Also, you can solve this using your own function like below:
/**
* Last date of a month of a year
*
* @param[in] $date - Integer. Default = Current Month
*
* @return Last date of the month and year in yyyy-mm-dd format
*/
function last_day_of_the_month($date = '')
{
$month = date('m', strtotime($date));
$year = date('Y', strtotime($date));
$result = strtotime("{$year}-{$month}-01");
$result = strtotime('-1 second', strtotime('+1 month', $result));
return date('Y-m-d', $result);
}
$a_date = "2009-11-23";
echo last_day_of_the_month($a_date);
Upvotes: 17
Reputation: 430
I am late but there are a handful of easy ways to do this as mentioned:
$days = date("t");
$days = cal_days_in_month(CAL_GREGORIAN, date('m'), date('Y'));
$days = date("j",mktime (date("H"),date("i"),date("s"),(date("n")+1),0,date("Y")));
Using mktime() is my go to for complete control over all aspects of time... I.E.
echo "<br> ".date("Y-n-j",mktime (date("H"),date("i"),date("s"),(11+1),0,2009));
Setting the day to 0 and moving your month up 1 will give you the last day of the previous month. 0 and negative numbers have the similar affect in the different arguements. PHP: mktime - Manual
As a few have said strtotime isn't the most solid way to go and little if none are as easily versatile.
Upvotes: 1
Reputation: 61
An other way using mktime and not date('t') :
$dateStart= date("Y-m-d", mktime(0, 0, 0, 10, 1, 2016)); //2016-10-01
$dateEnd = date("Y-m-d", mktime(0, 0, 0, 11, 0, 2016)); //This will return the last day of october, 2016-10-31 :)
So this way it calculates either if it is 31,30 or 29
Upvotes: 2
Reputation: 121
Using Zend_Date it's pretty easy:
$date->setDay($date->get(Zend_Date::MONTH_DAYS));
Upvotes: 2
Reputation: 1
This a much more elegant way to get the end of the month:
$thedate = Date('m/d/Y');
$lastDayOfMOnth = date('d', mktime(0,0,0, date('m', strtotime($thedate))+1, 0, date('Y', strtotime($thedate))));
Upvotes: -2
Reputation: 21535
Try this , if you are using PHP 5.3+,
$a_date = "2009-11-23";
$date = new DateTime($a_date);
$date->modify('last day of this month');
echo $date->format('Y-m-d');
For finding next month last date, modify as follows,
$date->modify('last day of 1 month');
echo $date->format('Y-m-d');
and so on..
Upvotes: 20
Reputation: 3813
If you use the Carbon API extension for PHP DateTime, you can get the last day of the month with:
$date = Carbon::now();
$date->addMonth();
$date->day = 0;
echo $date->toDateString(); // use toDateTimeString() to get date and time
Upvotes: 7
Reputation: 14236
There are ways to get last day of month.
//to get last day of current month
echo date("t", strtotime('now'));
//to get last day from specific date
$date = "2014-07-24";
echo date("t", strtotime($date));
//to get last day from specific date by calendar
$date = "2014-07-24";
$dateArr=explode('-',$date);
echo cal_days_in_month(CAL_GREGORIAN, $dateArr[1], $dateArr[0]);
Upvotes: 1
Reputation: 4049
Here is a complete function:
public function get_number_of_days_in_month($month, $year) {
// Using first day of the month, it doesn't really matter
$date = $year."-".$month."-1";
return date("t", strtotime($date));
}
This would output following:
echo get_number_of_days_in_month(2,2014);
Output: 28
Upvotes: 1
Reputation: 79
I have wrapped it in my date time helper class here
https://github.com/normandqq/Date-Time-Helper
using
$dateLastDay = Model_DTHpr::getLastDayOfTheMonth();
And it is done
Upvotes: 0
Reputation: 21182
I know this is a little bit late but i think there is a more elegant way of doing this with PHP 5.3+
by using the DateTime class :
$date = new DateTime('now');
$date->modify('last day of this month');
echo $date->format('Y-m-d');
Upvotes: 165
Reputation: 7
function first_last_day($string, $first_last, $format) {
$result = strtotime($string);
$year = date('Y',$result);
$month = date('m',$result);
$result = strtotime("{$year}-{$month}-01");
if ($first_last == 'last'){$result = strtotime('-1 second', strtotime('+1 month', $result)); }
if ($format == 'unix'){return $result; }
if ($format == 'standard'){return date('Y-m-d', $result); }
}
Upvotes: -1
Reputation: 156
$date1 = $year.'-'.$month;
$d = date_create_from_format('Y-m',$date1);
$last_day = date_format($d, 't');
Upvotes: 3
Reputation: 10079
You can also use it with datetime
$date = new \DateTime();
$nbrDay = $date->format('t');
$lastDay = $date->format('Y-m-t');
Upvotes: 4
Reputation: 6232
This should work:
$week_start = strtotime('last Sunday', time());
$week_end = strtotime('next Sunday', time());
$month_start = strtotime('first day of this month', time());
$month_end = strtotime('last day of this month', time());
$year_start = strtotime('first day of January', time());
$year_end = strtotime('last day of December', time());
echo date('D, M jS Y', $week_start).'<br/>';
echo date('D, M jS Y', $week_end).'<br/>';
echo date('D, M jS Y', $month_start).'<br/>';
echo date('D, M jS Y', $month_end).'<br/>';
echo date('D, M jS Y', $year_start).'<br/>';
echo date('D, M jS Y', $year_end).'<br/>';
Upvotes: 31
Reputation: 331
Your solution is here..
$lastday = date('t',strtotime('today'));
Upvotes: 11
Reputation: 1664
There is also the built in PHP function cal_days_in_month()?
"This function will return the number of days in the month of year for the specified calendar." http://php.net/manual/en/function.cal-days-in-month.
echo cal_days_in_month(CAL_GREGORIAN, 11, 2009);
// = 30
Upvotes: 97
Reputation: 25687
You can use "t
" in date function to get the number of day in a particular month.
The code will be something like this:
function lastDateOfMonth($Month, $Year=-1) {
if ($Year < 0) $Year = 0+date("Y");
$aMonth = mktime(0, 0, 0, $Month, 1, $Year);
$NumOfDay = 0+date("t", $aMonth);
$LastDayOfMonth = mktime(0, 0, 0, $Month, $NumOfDay, $Year);
return $LastDayOfMonth;
}
for($Month = 1; $Month <= 12; $Month++)
echo date("Y-n-j", lastDateOfMonth($Month))."\n";
The code is self-explained. So hope it helps.
Upvotes: -3
Reputation: 16952
You could create a date for the first of the next month, and then use strtotime("-1 day", $firstOfNextMonth)
Upvotes: 17