CODEWITHSUNDEEP
phpcodeigniter
programar
programar

Reputation: 9

Print results of a form on the same page in CodeIgniter

In normal PHP, you can send a form on the same page:

<form action = "" method = "POST">
    <input type = "text" name = "hi" value = "hi"/>
    <input type = "submit" name = "send" value = "Send"/>
</form>
<?
   if (isset($_POST['send'])) 
   echo $_POST['hi'];
?>

How can I do this in CodeIgniter?

I've tried this, but I don't know how to do it:

View:

<? echo form_open('form'); ?>
.....
</form>
<?
if (isset($_POST['data'])){
    $array = $data;
    foreach ($array as $array){
       echo array_sum($array)/count($array)."<br>";
    }
}
?>

Controller:

function index() {
    $name = $this->input->post('select');
    $this->load->model('select');
    $data['result'] = $this->select->index();
    $this->load->view('theview', $data);
}

Upvotes: 0

Views: 4807

Answers (4)

theB3RV
theB3RV

Reputation: 924

This will get you what you need from the post field,

$var = $this->input->get_post('some_data', TRUE);

but if the field is blank (when first entering the page) you might run into a problem with the variable not being defined. So be sure to set the following in your controller:

$var = NULL; $var = $this->input->get_post('some_data', TRUE);
$data = array('var' => $var);
$this->load->view('some_view', $data);

In the view if you call echo $var you should get the output from the post, or nothing if the variable is NULL.

Upvotes: 0

Chetan Gawai
Chetan Gawai

Reputation: 2401

You can submit the form using ajax request so that the page is not refreshed and the results are seen on the same page.Sample code :: View :

 <?php
$attributes = array('id'=>'profile-form','name'=>'personal_pro_form');
echo form_open('update_user_profile',$attributes);?>
<label class="control-label myprofilefont" for="email"> Email Address:<em  class="colorred" >*</em></label>
  <input type="text" id="email" placeholder="Email Address" name="user_email_id" value=>
                     ..
   <img src="submit-button.png"  id="Submit_Personal_Details">
   </form>
  $('#Submit_Personal_Details').live('click',function() {
  $.ajax({
             url:'update_user_profile',
            type:"POST",
            data:{'user_email_id':uemail,...},
            success:function(response){
            },
            error:function(req,status,error){
                alert(error);

            }
        });//end of ajax

}

Controller:

 function update_user_profile() {
... 

}

Upvotes: 1

JamesN
JamesN

Reputation: 387

you can do like this : PHP 

function index(){

    if($_SERVER['REQUEST_METHOD']=="GET")
    {
        $data['hi'] = "";
    }else //if POST
    {
        $data['hi'] = $this->input->post("hi");
    }
    //load one view for both GET and POST
    $this->load->view('theview', $data);
}

HTML

<form action = "URL_TO_INDEX_FUNCTION" method = "POST">
    <input type = "text" name = "hi" value = "hi"/>
    <input type = "submit" name = "send" value = "Send"/>
</form>
<?
   if (isset($hi) && $hi != "") 
        echo $hi;
?>

Upvotes: 0

dcd0181
dcd0181

Reputation: 1503

If your view is at view/controller/index.php, then in your view, simply use

echo form_open('controller/index');
...

if(isset($hi))echo $hi

And in your controller/index method just put something like

function index() {
    if($_POST){
        if (isset($_POST['send'])){
            $this->set('hi', $_POST['hi']);
        }
    }else{
        $name = $this->input->post('select');
        $this->load->model('select');
        $data['result'] = $this->select->index();
        $this->load->view('theview', $data);
    }
}

Upvotes: 0

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