CODEWITHSUNDEEP
php
Terion
Terion

Reputation: 2506

How to simulate non existing method error in __call?

Maybe strange question, but... I have a magic __call method, that return instances of certain classes, or, if there are no such class, calls same method in underlying object.

public function __call($name, $arguments)
{
    $class = 'My\\Namespace\\' . $name;

    if (class_exists($class, true)) {

        $reflect = new \ReflectionClass($class);
        return $reflect->newInstanceArgs($arguments);

    } elseif (is_callable([$this->connector, $name])) {

        return call_user_func_array([&$this->connector, $name], $arguments);
    } else {
        // ????
    }
}

But what to do in else block? Can I simulate undefined method error? Or what exception to throw would be correct?

Upvotes: 31

Views: 4267

Answers (1)

haim770
haim770

Reputation: 49105

You can trigger PHP errors manually using trigger_error:

trigger_error('Call to undefined method '.__CLASS__.'::'.$name.'()', E_USER_ERROR);

See http://php.net/manual/en/function.trigger-error.php

Upvotes: 31

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