Reputation: 26259
I've got functions, which sometimes return NaNs with float('nan')
(I'm not using numpy).
How do I write a test for it, since
assertEqual(nan_value, float('nan'))
is just like float('nan') == float('nan')
always false. Is there maybe something like assertIsNan
? I could not find anything about it…
Upvotes: 37
Views: 19766
Reputation: 305
Keying off of @user3503711's answer, the following worked for me:
numpy.isnan(nan_value)
I am using numpy==1.22.2. See https://numpy.org/doc/1.22/reference/generated/numpy.isnan.html
Upvotes: 2
Reputation: 2066
Update with NumPy: I know the OP is not using numpy
. However, I had to use numpy
and didn't find any post. So I'll leave the answer here for anybody that may need help. It also works perfectly with unittest
library.
import numpy as np
np.testing.assert_equal(nan_value, np.nan)
Upvotes: 6
Reputation: 468
math.isnan(x)
will raise a TypeError
if x
is neither a float
nor a Real
.
It's better to use something like this :
import math
class NumericAssertions:
"""
This class is following the UnitTest naming conventions.
It is meant to be used along with unittest.TestCase like so :
class MyTest(unittest.TestCase, NumericAssertions):
...
It needs python >= 2.6
"""
def assertIsNaN(self, value, msg=None):
"""
Fail if provided value is not NaN
"""
standardMsg = "%s is not NaN" % str(value)
try:
if not math.isnan(value):
self.fail(self._formatMessage(msg, standardMsg))
except:
self.fail(self._formatMessage(msg, standardMsg))
def assertIsNotNaN(self, value, msg=None):
"""
Fail if provided value is NaN
"""
standardMsg = "Provided value is NaN"
try:
if math.isnan(value):
self.fail(self._formatMessage(msg, standardMsg))
except:
pass
You can then use self.assertIsNaN()
and self.assertIsNotNaN()
.
Upvotes: 13