CODEWITHSUNDEEP
xsltattributesxslt-1.0
Sergej Popov
Sergej Popov

Reputation: 3021

XSLT: apply templates inside copy of the element

I need to output copy of element with all its attributes and apply-templates on children inside. main problem is that attributes are unknown.

XML:

<elem attrA="a" attrB="b" ... attrN="n">
  <child><child>
  <child><child>
</elem>

I have attempted to loop over all attributes but, can't get it working.

<xsl:template match="elem">
  <xsl:element name="name(.)">
    <xsl:for-each select="@*">
      <xsl:attribute name="name()">
        <xsl:value-of select="."/>
      </xsl:attribute>
    </xsl:for-each>
    <xsl:apply-templates />
  </xsl:element>
</xsl:template>

Required output:

<elem attrA="a" attrB="b" ...="" attrN="n">
  <processed-child></processed-child>
  <processed-child></processed-child>
</elem>

Given child template:

<xsl:template match="child">
  <processed-child><xsl:value-of select="."/></processed-child>
</xsl:template>

Edit:

XSLT 1.0

Upvotes: 3

Views: 7645

Answers (2)

Sergej Popov
Sergej Popov

Reputation: 3021

Just to add to Tomalak's answer, the final solution was enhanced a bit to enable text rendering around tags. (It was not described in original post, but was a requirement)

Complete solution:

<xsl:template match="elem">
  <xsl:copy>
    <xsl:copy-of select="@*" />
    <xsl:apply-templates select="*|text()" />
  </xsl:copy>
</xsl:template>

<xsl:template match="text()"><xsl:value-of select="."/></xsl:template>

Upvotes: 2

Tomalak
Tomalak

Reputation: 338118

Does

<xsl:template match="elem">
  <xsl:copy>
    <xsl:copy-of select="@*" />
    <xsl:apply-templates select="*" />
  </xsl:copy>
</xsl:template>

not work?

Upvotes: 4

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