Reputation: 21
Using only for or while statements, I'm trying to come up with a program to generate and print a table of the first 10 factorials. Here's my code:
for (count = 1; count<=10; ++count)
{
n = count;
while (n > 0){
count *= (count-1);
n -= 1;
}
NSLog(@" %2g %3g", count, factorial);
}
I don't understand why this is not working. It never gets out of the loop and goes on forever. What's the correction? Thank you!
Upvotes: 2
Views: 4687
Reputation: 17902
In Math, n! is the same thing as Γ(n+1) (see: http://en.wikipedia.org/wiki/Gamma_function)
So just use:
-(float)factorial:(float)number1 {
return tgammaf(++number1);
}
This will even work for floats and negative numbers,
other solutions posted are long and extraneous and only work with positive integers.
Upvotes: 4
Reputation: 21996
During the first loop iteration count is 1 and so also n is 1, then you enter the while and you set count to zero (count-1), and decrease n which becomes zero and you exit the while. So during the second loop iteration count will be zero. You keep decreasing count and it never gets increased, so you never exit the loop until a numeric overflow occurs.
You're doing it harder that what it is (and also inefficient) . Is enough that you keep multiplying n for count to get the factorial:
int n=1;
for (count = 1; count<=10; ++count)
{
n*= count;
NSLog(@"%d",n);
}
Upvotes: 1
Reputation:
The reason:
count *= (count-1);
Since count
starts at 1, it will always be reset to 0
, so the count <= 10
condition of the outer loop will always be true, hence the infinite looping.
And you're overcomplicating it anyway.
for (int i = 1; i <= 10; i++) {
int r = 1, n = i;
while (n)
r *= n--;
printf("%d! = %d\n", i, r);
}
Upvotes: 4