CODEWITHSUNDEEP
pythonfile
Mika H.
Mika H.

Reputation: 4339

Getting tree structure of directories

I was trying to use the code given in this StackOverflow answer. However, I don't understand what the line 

level = root.replace(startpath, '').count(os.sep)

is supposed to do.

Also, when I ran the code, it gave an error ValueError: zero length field name in format on the line 

print('{}{}/'.format(indent, os.path.basename(root)))

Upvotes: 1

Views: 276

Answers (2)

perreal
perreal

Reputation: 98108

Here:

root.replace(startpath, '').count(os.sep)

The root is the current directory of the walk.

root.replace(startpath, '')

removes the startpath from the root to get the path relative to the startpath.

root.replace(startpath, '').count(os.sep)

counts the number of os.seps, for example / for Linux, within this relative path. This count is the depth of the current directory relative to the startpath.

Upvotes: 2

Piotr Jaszkowski
Piotr Jaszkowski

Reputation: 1178

level = root.replace(startpath, '').count(os.sep)

It's calculating level of indentation for printing object (dir/file) name. It's getting rid of startpath as it's common for every listed file and it would look bad to have everything indented by +10 tabs :) os.sep returns path separator like '/' on Linux.

About that error, try: print('{0}{1}/'.format(indent, os.path.basename(root))) There you have some examples: http://docs.python.org/2/library/string.html#format-examples Probably your Python is not 2.7+

Upvotes: 2

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