CODEWITHSUNDEEP
shellsedawk
irappa
irappa

Reputation: 749

replacing matching columns using sed/awk/

How can I achieve this using awk/sed or any other scripting commands.

1) Read a file with many rows containing 26 digits in each line 2)Using shell scripting replace 07 with 08 only in 25th and 26th column of each row if 07 is found

Thankyou.

Upvotes: 1

Views: 207

Answers (3)

potong
potong

Reputation: 58578

This might work for you (GNU sed):

sed -r 's/^(.{24})07/\108/' file

Upvotes: 1

iruvar
iruvar

Reputation: 23404

With awk

awk  'BEGIN{FS=""; OFS=""}{if ($25$26 == "07") {$25="0"; $26="8"}{print}}'

Upvotes: 2

Kent
Kent

Reputation: 195289

if you are sure each row in your file has 26 digits. (length 26), you could:

sed 's/07$/08/' file

Upvotes: 1

Related Questions