CODEWITHSUNDEEP
cassembly
Sheldon
Sheldon

Reputation: 2628

Simple Increment in assembler

I'm stuck with this. I'm self studying assenbler and translating some basics instructions. But i can't with this one.

Can anyone help me, please?

int
secuencia ( int n, EXPRESION * * o )
{
  int a, i;
  for ( i = 0; i < n; i++ ){

    a = evaluarExpresion( *o );

    // Im trying to do this: o++;
  __asm {
      mov eax,dword ptr [o] 
      mov ecx,dword ptr [eax] 
      inc [ecx]  
    }
  }
  return a ;
}

I wrote the inside for and works, but still don't know how to increment O

int
secuencia ( int n, EXPRESION * * o )
{
  int a, i;
  for ( i = 0; i < n; i++ ){

      __asm {

            mov eax,dword ptr [o] 
            mov ecx,dword ptr [eax] 
        push ebp
            mov ebp, esp
            push ecx

            call evaluarExpresion
        mov esp, ebp

        pop ebp

        mov a, eax
      }

    o++;
  }
  return a ;
}

Upvotes: 0

Views: 11983

Answers (2)

toto
toto

Reputation: 900

mov esi, o
add esi, 4 //increment is here

Line1 : We move your o pointer to the esi register. Line2: We increment your o pointer

or 

mov eax, o
mov esi, [eax]
add esi, 4

I don't understand perfectly what you are trying to do but I hope it helped!

Upvotes: 1

Artelius
Artelius

Reputation: 49089

There are two options:

Either:

  • move the value of o from memory into a register (eax, for example)
  • increment the register
  • move the value from the register back to memory

or

  • increment the value stored in memory directly

Try to use both methods.

Upvotes: 1

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