CODEWITHSUNDEEP
javaregex
Adithya
Adithya

Reputation: 2975

Regular Expression for message

I am trying to write a regular expression in eclipse which recognizes the string 

X.printStackTrace();

where 'X' will be the exception variable. My expression is as follows:

([^\*\/\/\s])(.*)\Q.printStackTrace();\E

This works correctly except on the 3rd line when there are multiple printStackTrace statements in single line.

/* e.printStackTrace();
   e.getMessage();
   e.printStackTrace();e.printStackTrace(); e.printStackTrace();
   e.printStackTrace();*/
/* e.printStackTrace();
   e.getMessage();*/
/*
// e.printStackTrace();
   e.getMessage();
*/

Can anyone let me know what should be the regular expression if i have to search only 

X.printStackTrace();

on the 3rd line?

Upvotes: 0

Views: 200

Answers (2)

NeverHopeless
NeverHopeless

Reputation: 11233

You might be looking at this:

((?:\w+.printStackTrace\(\);\s*)+?)

Check out matches here.

EDIT : (my regex output at Rubular)

/* e.printStackTrace();

e.getMessage();

e.printStackTrace();e.printStackTrace(); e.printStackTrace();

e.printStackTrace();*/

/*e.printStackTrace();

e.getMessage();/ /

//e.printStackTrace();

e.getMessage(); */

EDIT

For that we need to adjust the pattern to make greedy (+) to ungreedy (+?).

Upvotes: 0

sp00m
sp00m

Reputation: 48807

The problem is in the (.*) part: you have to lazy match using (.*?).

I would have used the following regex though: [^.\s]+\Q.printStackTrace();\E

Upvotes: 1

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