CODEWITHSUNDEEP
c++terminal
Frank Yang
Frank Yang

Reputation: 49

C++ program to print counting numbers

In case the title is not precisely revealing what I want to do, the following is my problem.

I want to write a c++ program in a Linux or Mac terminal to print numbers that keeps counting from 1, 2, 3 ... at the same position under a command line mode. For example, it is like displaying the number of percentage when your work is progressing(e.g. downloading something, installing software...).

I wrote a simple for-loop to print numbers and use usleep(1000); for a delay of 1 second before printing next number. Then I use cout << "\b"; trying to move cursor back to display coming number at the same position. However I fail to create the effect that I want, the numbers are printed in a line.

I am not a skillful c++ programmer and know very limited on programming in a terminal environment. Can anyone help to give me hint or sample code for this function? Thanks!!

Upvotes: 2

Views: 2764

Answers (2)

learner
learner

Reputation: 1982

This works in terminal for me (am using linux) #include #include using namespace std;

int main(int argc, char *argv[]) {
        int i;
        for(i=1;i<100;i++)
        {
                cout<<"\b\b\b"<<i;
                cout.flush();
                sleep(1);
        }
        return 0;
}

Upvotes: 0

Deepu
Deepu

Reputation: 7610

If you are in Linux Terminal you can also use the following code,

system("clear");
cout<<"\b";    
cout<<Your_Number;

// Repeat this in a loop and call the delay function

Upvotes: 2

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