CODEWITHSUNDEEP
pythonregex
user1050619
user1050619

Reputation: 20856

identifying position of the pattern match

I need to find the exact position where the string matched..

>>> pattern = 'Test.*1'
>>> str1='Testworld1'
>>> match = re.search(pattern,str1)
>>> match.group()
'Testworld1'

I need the position of 1(10th byte) from the 'Testworld1' string which matched the pattern .*1.

Upvotes: 1

Views: 101

Answers (2)

Jason Sperske
Jason Sperske

Reputation: 30416

You want to do two things. First make a group out of the .*1, then when accessing the group you can call .start() Like so:

>>> pattern = 'Test.*(1)'
>>> match = re.search(pattern,str1)
>>> match.group(1)
'1'
>>> match.start(1)
9

Upvotes: 6

Martin Ender
Martin Ender

Reputation: 44259

How about end()

>>> pattern = r'Test.*1'
>>> str1='Testworld1'
>>> match = re.search(pattern,str1)
>>> match.end()
10

For more complicated applications (where you are not just looking for the last position of the last character in your match), you might want to use capturing and start instead:

>>> pattern = r'Test.*(11)'
>>> str1='Testworld11'
>>> match = re.search(pattern,str1)
>>> match.start(1) + 1
10

Here, start(n) gives you the beginning index of the capture of the nth group, where groups are counted from left to right by their opening parentheses.

Upvotes: 3

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