CODEWITHSUNDEEP
javascripthtmltemplatesnesteddocumentfragment
Steven Vachon
Steven Vachon

Reputation: 3980

Accessing a nested DocumentFragment

I can navigate the elements perfectly fine in Chrome's console, but I cannot seem to get a reference to the nested DocumentFragment with childNodes or firstChild.

Here's the code in jsFiddle: http://jsfiddle.net/Ge8au/2/

Here's the code:

function withoutJquery(html)
{
    var temp = document.createElement("div");
    temp.innerHTML = html;

    var fragment = document.createDocumentFragment();
    var child;

    while (child = temp.firstChild)
    {
        fragment.appendChild(child);
    }

    return fragment.firstChild;
}


function withJquery(html)
{
    var fragment = document.createDocumentFragment();

    fragment.appendChild( jQuery.buildFragment([html],document) );

    return fragment.firstChild;
}


var ajaxHTML = "";
ajaxHTML += "<template>\n";
ajaxHTML += "    <div>asdf</div>\n";
ajaxHTML += "    <div>\n";
ajaxHTML += "        <span>asdf</span>\n";
ajaxHTML += "    </div>\n";
ajaxHTML += "</template>";


// Gives the <template>
console.log( withoutJquery(ajaxHTML) );
console.log( withJquery(ajaxHTML) );

// Where are the <div>'s?
console.log( withoutJquery(ajaxHTML).childNodes.length );
console.log( withJquery(ajaxHTML).childNodes.length );

Upvotes: 0

Views: 2809

Answers (1)

jcsanyi
jcsanyi

Reputation: 8174

Try returning fragment.firstChild.content instead of fragment.firstChild.

Since this appears to vary slightly by browser, a better solution would be something like this:

var toReturn = fragment.firstChild;
return (toReturn.content ? toReturn.content : toReturn.childNodes);

It looks like there's some confusion by browser about whether the childNodes is needed as well - with the above code, you can probably remove childNodes from the console.log() statements.

Upvotes: 1

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