CODEWITHSUNDEEP
phpcodeignitercodeigniter-2
Sheeshkamal Vishwakarma
Sheeshkamal Vishwakarma

Reputation: 1

getting values of second select from db based of first select box selection in codeigniter

I Need help on how can i get values of second select box based on first select box

This is view:

$(document).ready(function() {

$('#state').change(function() {
// Get an instance of the select, and it's value.
    var state = $(this),
    stateID = state.val();
// Add if statement to check if the new state id
// is different to the last to prevent loading the same
// data again.

// Do the Ajax request.
$.ajax({
    url : 'http://localhost/ci_ajax/select/get_cities/'+stateID, // Where to.
    dataType : 'json', // Return type.
    success : function(data) { // Success :)
        // Ensure we have data first.
        if(data && data.Cities) {
            // Remove all existing options first.
            state.find('option').remove();
            // Loop through each city in the returned array.
            for(var i = 0; i <= data.Cities.length; i++) {
                // Add the city option.
                state.append($('option').attr({
                    value : data.Cities[i].value
                }).text(data.Cities[i].city));
            }
        }
    },
    error : function() {
        // Do something when an error happens?
    }
});

}); });

<form action="" method="post">
<select name="state" id="state">
    <option>Select</option>
    <?php foreach($states as $row):?>
        <option value="<?php echo $row->id?>"><?php echo $row->states;?></option>
    <?php endforeach;?>
</select>
<select id="cities" name="cities">
    <option>Select</option>
</select>

This is controller:

class Select extends CI_Controller{

function index(){

    $data['states']=$this->load_state();
    $this->load->view('form',$data);
}

function load_state(){

    $this->load->model('data_model');

    $data['states']=$this->data_model->getall_states();

    return $data['states'];
}

function get_cities() {
     // Load your model.
    $this->load->model('data_model');
    // Get the data.
    $cities = $this->data_model->get_cities();
    // Specify that we're returning JSON.
    header('content-type: application/json');
    // Return a JSON string with the cities in.
    return json_encode(array('Cities' => $cities));
}

}

This is model:

class Data_model extends CI_Model{

function getall_states(){

    $query=$this->db->get('states');
    if($query->num_rows()>0){
        foreach($query->result() as $row){
            $data[]=$row;
        }
        return $data;
    }

}

function get_cities(){

    $this->db->select('id,cities');
    $this->db->from('cities');
    $this->db->where('s_id',$this->uri->segment(3));
    $query=$this->db->get();

    if($query->num_rows()>0){
        foreach($query->result() as $row){
            $data[]=$row;
        }
        return $data;
    }

}

}

Please help on this hopefully provide the correct code.

Upvotes: 0

Views: 1570

Answers (1)

Bad Wolf
Bad Wolf

Reputation: 8349

Because you are accessing the get_cities() function directly, rather than from another function in the controller, your return statement will not actually print the json array to the page.

return json_encode(array('Cities' => $cities));

There are 3 ways to print it: the first is to print or echo the json array (bad practice), the second is to use a view that prints the raw text sent to it. I.E.

$this->load->view('raw', array('data' => json_encode(array('Cities' => $cities)));

With raw.php being just:

<?php print $data; ?>

Or finally you can use the set_output() function in the output class like this:

$this->output->set_output(array('data' => json_encode(array('Cities' => $cities)));

You may also want to make your function load_state() private if it is only going to be accessed from the index() function.

You may have other problems with your code but that is the most obvious one.

Upvotes: 0

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