CODEWITHSUNDEEP
pythonjsonappendnewlinedump
Victor S
Victor S

Reputation: 879

Python JSON dump / append to .txt with each variable on new line

My code creates a dictionary, which is then stored in a variable. I want to write each dictionary to a JSON file, but I want each dictionary to be on a new line.

My dictionary:

hostDict = {"key1": "val1", "key2": "val2", "key3": {"sub_key1": "sub_val2", "sub_key2": "sub_val2", "sub_key3": "sub_val3"}, "key4": "val4"}

Part of my code:

g = open('data.txt', 'a')
with g as outfile:
  json.dump(hostDict, outfile)

This appends each dictionary to 'data.txt' but it does so inline. I want each dictionary entry to be on new line. Any advice would be appreciated.

Upvotes: 87

Views: 198932

Answers (2)

Sayali Sonawane
Sayali Sonawane

Reputation: 12599

To avoid confusion, paraphrasing both question and answer. I am assuming that user who posted this question wanted to save dictionary type object in JSON file format but when the user used json.dump, this method dumped all its content in one line. Instead, he wanted to record each dictionary entry on a new line. To achieve this use: 

with g as outfile:
  json.dump(hostDict, outfile,indent=2)

Using indent = 2 helped me to dump each dictionary entry on a new line. Thank you @agf. Rewriting this answer to avoid confusion.

Upvotes: 21

agf
agf

Reputation: 176780

Your question is a little unclear. If you're generating hostDict in a loop:

with open('data.txt', 'a') as outfile:
    for hostDict in ....:
        json.dump(hostDict, outfile)
        outfile.write('\n')

If you mean you want each variable within hostDict to be on a new line:

with open('data.txt', 'a') as outfile:
    json.dump(hostDict, outfile, indent=2)

When the indent keyword argument is set it automatically adds newlines.

Upvotes: 169

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