Reputation: 7388
I have set up this example:
class UsefulClass {
public:
int id;
const bool operator< (const UsefulClass &other) const {
return this->id > other.id;
}
UsefulClass(int _id): id(_id) {
std::cout << "constructing " << id << std::endl;
}
~UsefulClass() {
std::cout << "destructing " << id << std::endl;
}
};
std::set<UsefulClass> set;
void create() {
UsefulClass object_1(1);
UsefulClass object_2(2);
set.insert(object_1);
set.insert(std::move(object_2));
std::cout << "create end" << std::endl;
}
int main() {
create();
std::cout << "main end" << std::endl;
}
I am expecting that the objects get destructed once when set
gets deleted at the end of the program. But the objects get deleted twice:
constructing 1
constructing 2
create end
destructing 2
destructing 1
main end
destructing 1
destructing 2
Why is set.insert
creating a copy here?
Upvotes: 2
Views: 233
Reputation: 12668
To illustrate whatever everybody has said before me, just create this simple example (it uses a new copy constructor for the set to use and uses a global variable to generate different id
s each time a constructor is executed ---it's been tested, so you can put it in a file and compile):
#include <iostream>
#include <string>
#include <set>
using namespace std;
class UsefulClass {
static int instance;
public:
int id;
int i;
const bool operator<(const UsefulClass &other) const {
return id < other.id;
}
UsefulClass(int i){
id = instance++;
this->i = i;
cout << "constructing "
<< id
<< ":"
<< this->i
<< endl;
}
UsefulClass(const UsefulClass& other) {
id = instance++;
i = other.i;
cout << "constructing "
<< id
<< ":"
<< i
<< endl;
}
~UsefulClass(){
cout << "destructing "
<< id
<< ":"
<< i
<< endl;
}
};
int UsefulClass::instance = 0;
std::set<UsefulClass> myset;
void create() {
UsefulClass object_1(1);
UsefulClass object_2(2);
myset.insert(object_1);
/* please, explain what you mean with std::move, or which move
* have you used for the next statement. All i have is
* std::move(... ) for strings, but you have not defined
* string UsefulClass::operator string();
*/
myset.insert(/*std::move*/(object_2));
cout << "create end"
<< endl;
}
int main() {
create();
cout << "main end"
<< std::endl;
}
so you'll get a different instance id whenever you create a UsefulClass object and you'll see that when inserting into the set they are being copied as new instances. You'll see when each object is being created and when they are being deleted.
$ pru
constructing 0:1
constructing 1:2
constructing 2:1
constructing 3:2
create end
destructing 1:2
destructing 0:1
main end
destructing 2:1
destructing 3:2
Upvotes: 0
Reputation: 17163
Rule of 3 applies to your case, if you print from dtor and want meaningful trace you should instrument copy (and maybe move) ctor also.
If you do that output will make sense and things should be properly paired.
Upvotes: 1
Reputation: 14341
object_1 and object_2 are created on stack and will be destroyed once the create() function ends. They need to be copied in the memory managed by set's allocator.
If you redefine the copy constructor, to trace its execution, you'll notice it is called at both inserts.
Upvotes: 2
Reputation: 72346
The objects in the set
are different from the objects local to create()
. The ones in the set
are constructed using a copy constructor and move constructor, not the constructor UsefulClass(int)
, so you don't see their construction. The local objects get destroyed when the function create()
returns, and then the objects in the set
get destroyed at global cleanup after main
ends.
Upvotes: 4
Reputation: 4674
Because your objects get copied on insertion into the set. Hence, when the create()
function returns, the two local objects are destroyed. After main
ends, the two copies that are in the set are destroyed, leading to the second pair of messages.
Upvotes: 0