Reputation: 361
function isChongHao(ary,i,j)
if ary(i-1,j)<>0 or ary(i+1,j) then
isChongHao=true
exit function
end if
isChongHao=false
end function
Upvotes: 1
Views: 109
Reputation: 24182
function isChongHao($ary, $i, $j) {
if($ary[$i-1][$j] != 0 || $ary[$i+1][$j]) {
return true;
}
return false;
}
--I suppose $ary contains a name of a function.--
Ooops, strike that: Joel thanks, I totally missed the fact that it was vbscript!!! O.o Now maybe it is better...
Upvotes: 4
Reputation: 10200
Assuming ary is an array
function isChongHao($ary,$i,$j) {
return (($ary[$i-1][$j] || $ary[$i+1][$j]) ? true : false);
}
Assuming ary is a function
function isChongHao($ary,$i,$j) {
return (($ary($i-1,$j) || $ary($i+1,$j)) ? true : false);
}
Upvotes: 0
Reputation: 758
function isChongHao($ary, $i, $j)
{
return ($ary[$i-1][$j] || $ary[$i+1][$j]);
}
You should probably check to ensure those indexes are set in the array beforehand, though, with an isset() call.
Upvotes: 1