CODEWITHSUNDEEP
pythonwhile-loop
muros
muros

Reputation: 337

How to create a function that loops back to the first player from the last player?

This is what I got so far. This game can have multiple players up to len(players).

I'd like it to keep prompting the different players each time to make their move. So, for example, if there are 3 players A B C, if it was player's A turn, I want the next player to be player B, then the next player to be C, and then loop back to player A.

Using only while loops, if statements, and booleans if possible.

PLAYERS = 'ABCD'

def next_gamer(gamer):
    count = 0
    while count < len(GAMERS):
    if gamer == GAMERS[0]:
          return GAMERS[count + 1]
    if gamer == GAMERS[-1]
          return GAMER[0]
    count = count + 1

Upvotes: 0

Views: 287

Answers (3)

junkaholik
junkaholik

Reputation: 81

If you can't use the .index() method, I think what you are trying to do is this:

    def next_gamer(gamer):
        count = 0
        while count < len(GAMERS):
            if gamer == GAMERS[count]:
                return GAMERS[count + 1]
            count = count + 1
        return GAMERS[0]

Upvotes: 2

junkaholik
junkaholik

Reputation: 81

You can just have your function return the next gamer in your list GAMERS using a simple statement like this one which works regardless of which gamer you are currently at in the game:

return GAMERS[GAMERS.index(gamer)+1]

unless the present gamer is the last in the list which you can test using the following if statement:

if GAMERS.index(gamer) == len(GAMERS) - 1:

return GAMERS[0]

in which case you return the first gamer.

Upvotes: 0

SylvainD
SylvainD

Reputation: 1763

My solution to your previous question, involving generators :

turn=0
def gameIsFinished():
    global turn
    turn = turn+1
    return turn >10

def cycle(iterable):
    while True:
        for item in iterable:
            if gameIsFinished():
                return
            yield item

for player in cycle([1,2,3]):
    print player

Upvotes: 0

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