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pythonsympyevaluate
sloan
sloan

Reputation: 329

Sympy function evaluation

I have a little question about sympy. I did load the library with :

from sympy import *

At some point of my program I would like to evaluate a function. 

x=Symbol('x', real=True)
sqrt(1-x).subs(x, 9).evalf()
>>> 2.82842712474619*I

Sympy answer me complex value but i would like an error as in basic python : 

sqrt(-1)
>>> ValueError: math domain error

Someone know how to do that using sympy?

Upvotes: 2

Views: 4185

Answers (1)

zmo
zmo

Reputation: 24812

I may be wrong, but I don't think you can make it yell that way, because that's a scientific library so it is made for supporting imaginary numbers, but you can change it a bit:

x=Symbol('x', real=True)
v = sqrt(1-x).subs(x, 9).evalf()

if not v.is_real:
    raise ValueError, "math domain error"

or you can create a function:

def assert_real(v):
    if not v.is_real:
        raise ValueError, "math domain error"
    return v

so you can do:

x = Symbol('x', real=True)
v = assert_real(sqrt(1-x).subs(x, 9).evalf())

Upvotes: 3

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