CODEWITHSUNDEEP
javaregex
user86834
user86834

Reputation: 5645

Regular expression to get the last parts segments of a URL

How can I get the last two parts of a URL. For example if a URL is 

http://stackoverflow/java/regex

I would like to get the following

 java/regex

The regex "./(.)" will give me the last segment but I struggling to get the last two parts.

Upvotes: 0

Views: 2806

Answers (6)

Mena
Mena

Reputation: 48404

You can try this: 

String url = "http://stackoverflow/java/regex";
Pattern pattern = Pattern.compile(".+/(.+/.+)$");
Pattern otherPattern = Pattern.compile(".+/(.+)/.+$");
Matcher matcher = pattern.matcher(url);
if (matcher.find()) {
    System.out.println(matcher.group(1));
}
matcher = otherPattern.matcher(url);
if (matcher.find()) {
    System.out.println(matcher.group(1));
}

Output: 

java/regex
java

Upvotes: 1

Brian Agnew
Brian Agnew

Reputation: 272257

I would use the existing URL class and the getPath() method to get the section following the host/port/protocol.

I'd certainly start with an existing class designed to break apart URL components and then work from there. If you use a regexp you're likely to run into and have to cater for lots of edge cases that the URL class already handles.

Upvotes: 0

Zoubiock
Zoubiock

Reputation: 1165

Why not casting your URL to URI and call method getPath() ?

Upvotes: 0

sanbhat
sanbhat

Reputation: 17622

You can use java.net.URL's getPath() method

URL url = new URL("http://stackoverflow/java/regex");
System.out.println(url.getPath());

Upvotes: 1

fge
fge

Reputation: 121710

Do NOT use regexes for this when Java has URI!

final URI uri = URI.create("http://stackoverflow/java/regex");
uri.getPath().subString(1); // returns "java/regex"

Upvotes: 7

futuretelematics
futuretelematics

Reputation: 1495

Simple!

It you have absolute urls: 

Pattern p = Pattern.compile("http://(^[/]+)/([^/]+)/([^/]+);
Matcher m = p.matcher(yourURL);
if (m.find()) {
    path1 = m.group(2);
    path2 = m.group(3);
}

Hope this helps!

Upvotes: 0

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