Reputation: 1217
In my program, the user types a Zip Code and gets as an output information related to the Zip Code (province, city, district). To do this, I use the Vlookup function. So, the user :
I use this code to do so :
If Range("J9").Value <> "N/A" Then 'if there is actually a zip code entered by the user (if not, it will be "N/A")
cityZip = Application.WorksheetFunction.VLookup(sMain.Range("J9").Value,
sZipCodes.Range("B2:E864"), 3, False)
barangayZip = Application.WorksheetFunction.VLookup(sMain.Range("J9").Value,
sZipCodes.Range("B2:E864"), 2, False)
provinceZip = Application.WorksheetFunction.VLookup(sMain.Range("J9").Value,
sZipCodes.Range("B2:E864"), 4, False)
sMain.Range("J7").Value = provinceZip
sMain.Range("J13").Value = cityZip
sMain.Range("J16").Value = barangayZip
Else
End If
It works perfectly when there is a Zip Code which is in my database. But if not, it crashes the execution of the program and I have an error message (like "execution error '1004', unable to read the Vlookup ...). How to modify my code to just say that if there is no match, then it should just do nothing? I don't know how to introduce this request in a Vlookup function.
Thanks in advance !
EDIT : here is my new code, after following Tim Williams suggestion :
'Using Zip Code
If Range("J9").Value <> "N/A" Then
provinceZip = Application.Lookup(sMain.Range("J9").Value, sZipCodes.Range("B2:E907"), 4, False)
If IsError(provinceZip) = False Then
cityZip = Application.Lookup(sMain.Range("J9").Value, sZipCodes.Range("B2:E907"), 3, False)
barangayZip = Application.Lookup(sMain.Range("J9").Value, sZipCodes.Range("B2:E907"), 2, False)
sMain.Range("J7").Value = provinceZip
sMain.Range("J13").Value = cityZip
sMain.Range("J16").Value = barangayZip
Else
'do nothing
End If
End If
My error is on this line :
provinceZip = Application.Lookup(sMain.Range("J9").Value, sZipCodes.Range("B2:E907"), 4, False)
=> Error 1004, invalid number of arguments
Upvotes: 5
Views: 19758
Reputation: 116
You changed from Vlookup to Lookup, which has less arguments. Using only 2 arguments, you should be fine: provinceZip = Application.Lookup(sMain.Range("J9").Value, sZipCodes.Range("B2:E907") )
Upvotes: 1
Reputation: 11
SafeVlookup is a good function. I am still learning VB. I changed like this and it works for me.
Function SafeVlookup(lookup_value, _
range_lookup, col_index, error_value) As Variant
.....
return_value = Application.WorksheetFunction.vlookup(lookup_value, _
range_lookup, col_index, error_value)
....
End Function
Hope I can use it like this.
Upvotes: -1
Reputation: 10328
You should read up on VBA error handling. A source such as http://www.cpearson.com/excel/errorhandling.htm might help. That said, try the following code.
You want something like:
Public Function SafeVlookup(lookup_value, table_array, _
col_index, range_lookup, error_value) As Variant
On Error Resume Next
Err.Clear
return_value = Application.WorksheetFunction.VLookup(lookup_value, _
table_array, col_index, range_lookup)
If Err <> 0 Then
return_value = error_value
End If
SafeVlookup = return_value
On Error GoTo 0
End Function
In your code you might call it like:
cityZip = SafeVlookup(sMain.Range("J9").Value, sZipCodes.Range("B2:E864"), 3, _
False, "")
The last parameter is the default value to return if the vlookup failed. So in this example it'd return an empty string.
Upvotes: 5
Reputation: 3332
I usually wrap the vlookup() with an iferror() which contains the default value.
The syntax would be as follows:
iferror(vlookup(....), <default value when lookup fails>)
You can also do something like this:
Dim result as variant
result = Application.vlookup(......)
If IsError(result) Then
' What to do if an error occurs
Else
' what you would normally do
End if
Upvotes: 2