CODEWITHSUNDEEP
jquery-ui
J. Ghyllebert
J. Ghyllebert

Reputation: 2027

Uncaught TypeError: Cannot read property 'left' of undefined

I can't seem to show a datepicker from jQuery UI on a hidden field as I get this error:

Uncaught TypeError: Cannot read property 'left' of undefined

When I use a regular text field, I don't seem to have a problem. I get this error with both jQuery UI 1.9.0 and 1.9.2, the version of jQuery is 1.8.3

html

<table>
    <tr>
        <td> 
            <small class="date_target">until <span>Dec. 31, 2013</span></small>
            <input type="hidden" class="end_date" />
        </td>
    </tr>
</table>

JS

$(".end_date").datepicker({
    dateFormat: 'yyyy-mm-yy',
    yearRange: '-00:+01'
});

$('.date_target').click(function () {
    $(this).next().datepicker('show');
});

I provided a (not) working example on this jsfiddle too

Upvotes: 11

Views: 43578

Answers (3)

zero0
zero0

Reputation: 877

It's because the input field is not visible to the browser (because it's hidden).

Try this:

<input type="text" style="height: 0px; width:0px; border: 0px;" class="end_date" />

and you are fine. Of course, you can add the extra style attributes to the CSS class "end_date". A "display:none" will not help, because then the field is fully invisible again.

Example also in a JS Fiddle.

Upvotes: 14

jasperjian
jasperjian

Reputation: 393

Let's check datepicker _findPos function

$.datepicker._findPos = function (obj) {
        var position,
            inst = this._getInst(obj),
            isRTL = this._get(inst, "isRTL");

        while (obj && (obj.type === "hidden" || obj.nodeType !== 1 || $.expr.filters.visible(obj))) {
            obj = obj[isRTL ? "previousSibling" : "nextSibling"];
        }

        position = $(obj).offset();        

        /*because position of invisible element is null, js will break on next line*/
        return [position.left, position.top]; 
    };

If target obj of datepicker is invisible, it will use the closest sibling position which is not invisible

There are several solutions：

Solution 1

Because of LTR, you can exchange position of two element

<tr>
    <td> 
        <input type="hidden" class="end_date" />
        <small class="date_target">until <span>Dec. 31, 2013</span></small>
    </td>
</tr>

Solution 2

Add an visible element next to the hidden element, so datepicker will find the visible element position

<tr>
    <td>
        <small class="date_target">until <span>Dec. 31, 2013</span></small>
        <input type="hidden" class="end_date" /><span>&nbsp;</span>
    </td>
</tr>

Solution 3

Redefine _findPos function, so you can set position of calendar wherever you want

$.datepicker._findPos = function (obj) {
        var position,
            inst = this._getInst(obj),
            isRTL = this._get(inst, "isRTL");

        while (obj && (obj.type === "hidden" || obj.nodeType !== 1 || $.expr.filters.visible(obj))) {
            obj = obj[isRTL ? "previousSibling" : "nextSibling"];
        }

        position = $(obj).offset();
        // if element type isn't hidden, use show and hide to find offset
        if (!position) { position = $(obj).show().offset(); $(obj).hide();}
        // or set position manually
        if (!position) position = {left: 999, top:999};
        return [position.left, position.top]; 
    };

Upvotes: 7

arcturus
arcturus

Reputation: 11

I had the same problem while using Bootstrap as well, cause I needed my datepicker to show with a button click.

This works:

<div class="form-group">
   <label class="sr-only" for="txtDate">Date</label>
   <input type="text" class="form-control input-sm" style="display: none;" id="txtDate">
   <button type="button" class="btn btn-default btn-sm" id="btnDate">
      <span class="glyphicon glyphicon-calendar"></span> Calendar
   </button>
</div>

This doesn't work:

<div class="form-group">
   <label class="sr-only" for="txtDate">Date</label>
   <input type="text" class="form-control input-sm" style="display: none;" id="txtDate">
</div>
<button type="button" class="btn btn-default btn-sm" id="btnDate">
   <span class="glyphicon glyphicon-calendar"></span> Calendar
</button>

JS:

$('#txtDate').datepicker({
   dateFormat: 'yy-mm-dd',
   showAnim: 'fade'
});
$("#btnDate").on('click', function(){
   $('#txtDate').datepicker('show');
});

So all I needed was to put the button on the same div element. In case anyone else has this problem.

Upvotes: 1

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