CODEWITHSUNDEEP
c++for-loop
Abdus Sattar Bhuiyan
Abdus Sattar Bhuiyan

Reputation: 3074

How can I print all values of for loop variable?

I wrote a program to print the hexadecimal values, octal values and the corresponding character, separated by hyphens, for the ASCII values between 40 and 126 (both inclusive). My code is:

#include<iostream>
using namespace std;
int main()
{
      int i;
      char c;
        for(i=40;i<=126;i++)
        {
            c=i;
            cout<<i<<"-"<<hex<<i<<"-"<<oct<<i<<"-"<<c<<"\n";
      }
      return 0;
}

it works fine but here some values of i are skiped. i.e 58,59 are not printed. I want to print for all values in 40 to 126 range. Have any suggestions?

Upvotes: 2

Views: 2416

Answers (3)

awesoon
awesoon

Reputation: 33651

If you want to print first as decimal, you should add std::dec stream manipulator:

cout << dec << i << "-" << hex << i << "-" << oct << i << "-" << c << "\n";
//      ^^^

Because after first loop's iteration, flag std::ios_base::oct oct` still remains.

Upvotes: 14

Jonathon Reinhart
Jonathon Reinhart

Reputation: 137398

Or you can use the good ol' C library:

#include <stdio.h>
int main()
{
    int i;
    for(i=40;i<=126;i++)
        printf("%d 0x%X  '%c' \n", i, i, i);

    return 0;
}

Upvotes: 0

Andreas Fester
Andreas Fester

Reputation: 36630

The last manipulator you used for each call to cout is oct, and the stream "remembers" that - so, when you output i the next time without manipulator, it still uses oct as output format. Simply use dec explicitly for the first output of i:

cout << dec << i << "-" << hex << i << "-" << oct << i << "-" << c <<"\n";

Upvotes: 6

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