Reputation: 1463
I am trying to resolve project euler problem no 12 with PHP but it is taking too much time to process. I came across with similar processing problems of PHP while solving previous problems and I had to solve them in C++ just to test whether my approach is correct or not. I want to know whether there is something wrong with my approach or somehow I can do something to make processing fast. Here is the code of my solution which works well for the triangle having 360 divisors. The link of problem is http://projecteuler.net/problem=12 and here is my code
<?php
set_time_limit(0);
ini_set('memory_limit', '1G');
$triangles = array(0);
$count = 1;
$numOfDivisiors = 0;
$lastTriangle = 0;
while($numOfDivisiors < 500){
$triangle = (int) $lastTriangle + (int) $count;
$factors = getFactors($triangle);
//$triangles[] = array('triangle' => $triangle, 'factors' => $factors, 'factorsCount' => count($factors));
$triangles[] = array('triangle' => $triangle, 'factorsCount' => count($factors));
$lastTriangle = $triangle;
$numOfDivisiors = count($factors);
$count++;
//echo '<pre>'; print_r(array('triangle' => $triangle, 'factorsCount' => count($factors), 'count' => $count)); echo '</pre>';
}
echo $numOfDivisiors; exit;
/**
for($i = 0 ; $i < 10 ; $i++){
}
**/
//echo '<pre>'; print_r($triangles); exit;
function getFactors($number){
$factors = array();
$break = false;
$count = 1;
while($break != true){
$remainder = $number % $count;
if($remainder == 0){
$factors[] = $count;
}
//echo $count." ".$number; exit;
if($count == $number){
$break = true;
}
$count++;
}
return $factors;
}
?>
Upvotes: 1
Views: 1359
Reputation: 18568
use some maths.
triangle numbers can be generated by
n(n+1) /2
and that if you can find the prime factors, Adding 1 to their powers and multiplying together gives the number of divisors.
My PHP solution takes around 4 seconds and i think i can speed that up also
Upvotes: 2
Reputation: 5657
There are several ways to speed up your solution. The first one I'd point you at is the following:
if a * b = c then both a and b are factors of c
One of a and b will be <= to the square root of c
this should help speed up your solution
Upvotes: 0