CODEWITHSUNDEEP
c++
timmz
timmz

Reputation: 2252

function not called with the same name as a class

Why the function bellow void i( ) is not called as in a 'Normal' function.

void i(){
    cout << 10 << endl;
}

int main(){
    class i { 
        int j;
    };

    i();// 

    return 0;
}

The normal behavior expected is to print 1O, but I did not getting anything, not a compiler warning nor the result.

Upvotes: 1

Views: 98

Answers (2)

Scott Jones
Scott Jones

Reputation: 2908

The inner i is shadowing the outer one. You are calling the default constructor of class i which does nothing in this case.

The solution is to explicitly scope the call, as ::i();

Upvotes: 8

Alexis
Alexis

Reputation: 2179

Because it's trying to call "i" in the current scope: You can call your function::i();

Upvotes: 1

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