CODEWITHSUNDEEP
cif-statementbreak
shafeeq
shafeeq

Reputation: 143

how to get out of "if" loop in c?

if(turn==2)
{
    if(forward)  /*then what to do if this if comes true for coming out of outer loop*/
        if(columnHead>0)
            {
            columnHead--;
            addr[columnHead] |=1<<(rowHead-1);
            }
        else
            {
            columnHead =7;
            addr[columnHead] |=1<<(rowHead-1);
            }
    if(rowTail!=(rowHead-1))
        {
        addr[columnHead+columnSize] &=~(1<<rowTail);
        columnSize++;
        rowTail++;
        }
    else
        {
        addr[columnTail] &=~(1<<columnTail);
        if(columnTail==0)columnTail=8;
        columnTail--;
        }
    back=1;
}

I want to come out of outer if loop if it satisfies condition if(forward)

Upvotes: 1

Views: 5476

Answers (6)

viraptor
viraptor

Reputation: 34145

I guess just putting an else in there will do what you want. Also, please put braces around big blocks - it makes the else part unambiguous.

if(turn==2)
{
    if(forward) {
        if(columnHead>0)
            {
            columnHead--;
            addr[columnHead] |=1<<(rowHead-1);
            }
        else
            {
            columnHead =7;
            addr[columnHead] |=1<<(rowHead-1);
            }
    } else {
        if(rowTail!=(rowHead-1))
            {
            addr[columnHead+columnSize] &=~(1<<rowTail);
            columnSize++;
            rowTail++;
            }
        else
            {
            addr[columnTail] &=~(1<<columnTail);
            if(columnTail==0)columnTail=8;
            columnTail--;
            }
        back=1;
    }

}

Version after the author's comment:

if(turn==2 && !forward) {
    if(rowTail!=(rowHead-1))
        {
        addr[columnHead+columnSize] &=~(1<<rowTail);
        columnSize++;
        rowTail++;
        }
    else
        {
        addr[columnTail] &=~(1<<columnTail);
        if(columnTail==0)columnTail=8;
        columnTail--;
        }
    back=1;
}

Upvotes: 1

Roee Gavirel
Roee Gavirel

Reputation: 19445

why go into the "if" in the first place.

change the outter if to:

if(turn==2 && forward) //not sure if your logic required `forward` or `!forward` you were ambiguous 
{
    //...
}

Upvotes: 0

Ishank
Ishank

Reputation: 2926

You can try giving the return 0; or return something; when you need to get out of the if, before that u may want to put the entire code in a c syntax function like- 

    (int)someFunction(int turn, int forward, 
int columnHead, int rowHead, int rowTail, int columnTail)/*have all the arguments with proper types declaration*/{
    //your code with return 0;
    }.

Upvotes: 0

Bathsheba
Bathsheba

Reputation: 234655

A standard idiom is to use while(true){/*your code here*/ break; } around the whole block and use break statements as appropriate which will take you to the end of the while brace. Just remember to include the final break or your program will loop.

Whatever you do, don't use a goto as they are considered very poor programming style.

Some folk, from the C days where while(true) would issue a compile warning, use for(;;) instead.

The odd thing is, thinking about this some more, you could use

do {
 /*your code here, using break for premature exit*/
} while (false);

which doesn't need the final break. Only I've never seen this in production code.

Upvotes: 2

keen
keen

Reputation: 3011

You should create function of this code, and return from the block where the condition becomes true.

Upvotes: 8

Adrian Jandl
Adrian Jandl

Reputation: 3015

You probably have to go the other direction, that means: You don't want to check wether if(forward) is true, but instead you want to do if(!forward).

Though you'd need to check what type forward is. I guess it's an integer though.

Upvotes: 0

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