CODEWITHSUNDEEP
javastring
NoNaMe
NoNaMe

Reputation: 6242

Replacing multiple char from a string in java

I have a PHP script <?=str_replace(array('(',')','-',' ','.'), "", $rs["hq_tel"])?> this is a string replace function that take array of chars and replace them if find any of the char in string. Is there any java equivalent of the function. I found some ways but some are using loop and some repeating the statements but not found any single line solution like this in java.

Thanks in advance.

Upvotes: 12

Views: 89245

Answers (4)

maqjav
maqjav

Reputation: 2434

If you don't know about regex you can use something more elaborated:

private static ArrayList<Character> special = new ArrayList<Character>(Arrays.asList('(', ')', '-', ' ', '.'));

public static void main(String[] args) {
    String test = "Hello(how-are.you ?";
    String outputText = "";

    for (int i = 0; i < test.length(); i++) {
        Character c = new Character(test.charAt(i));
        if (!special.contains(c))
            outputText += c;
        else
            outputText += "";
    }

    System.out.println(outputText);
}

Output: Hellohowareyou?

EDIT (without loop but with regex):

public static void main(String[] args) {
    String test = "Hello(how-are.you ?)";
    String outputText = test.replaceAll("[()-. ]+", "");

    System.out.println(outputText);
}

Upvotes: 3

Ganesh Rengarajan
Ganesh Rengarajan

Reputation: 2006

your solution is here..

Replace all special character

str.replaceAll("[^\\dA-Za-z ]", "");

Replace specific special character

str.replaceAll("[()?:!.,;{}]+", " ");

Upvotes: 21

Rahul
Rahul

Reputation: 45090

You can use a regex like this:

//char1, char2 will be replaced by the replacement String. You can add more characters if you want!
String.replaceAll("[char1char2]", "replacement");

where the first parameter is the regex and the second parameter is the replacement.

Refer the docs on how to escape special characters(in case you need to!).

Upvotes: 31

Funkytown
Funkytown

Reputation: 560

String.replaceAll(String regex, String replacement)

Upvotes: 2

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