Reputation: 1
I have this two class in c++
GUI.cpp
#include "AL_GUI.h"
#include <QtGui/QApplication>
#include "mainwindow.h"
GUI::GUI() {
}
void GUI::startGUI(){
int c=1;
char *array[10];
char** v = &array[0];
QApplication qa(c,v);
w.show();
qa.exec();
}
void GUI::notifyAlert(){
}
GUI::~GUI() {
// TODO Auto-generated destructor stub
}
GUI.h
#include <QtGui/QApplication>
#include "mainwindow.h"
#include "mainwindow.h"
#ifndef GUI_H_
#define GUI_H_
class GUI {
public:
GUI();
virtual ~GUI();
void startGUI();
void notifyAlert();
private:
MainWindow w;
};
#endif
But when i run this program i have the error: QWidget: Must construct a QApplication before a QPaintDevice
How can I declare MainWindow w in gui.h in such a way that I don't receive this error
Upvotes: 0
Views: 566
Reputation: 10827
I would have made w a pointer used a forward declaration for MainWindow and removed all the includes (including the 2 includes for mainwindow.h) from GUI.h. Then like the answer from Sebastian says construct the QApplication first.
AL_GUI.h
#ifndef GUI_H_
#define GUI_H_
class MainWindow;
class GUI {
public:
GUI();
virtual ~GUI();
void startGUI();
void notifyAlert();
private:
MainWindow* w;
};
gui.cpp
#include "AL_GUI.h"
#include <QtGui/QApplication>
#include "mainwindow.h"
GUI::GUI() : w(NULL)
{
}
void GUI::startGUI(){
int c=1;
char *array[10];
char** v = &array[0];
QApplication qa(c,v);
w = new MainWindow;
w->show();
qa.exec();
}
void GUI::notifyAlert(){
}
GUI::~GUI() {
delete w;
}
Upvotes: 0
Reputation: 71889
You can't (well, you can, but you shouldn't). The MainWindon declaration is right where it should be. The problem is that you attempt to create a GUI object before you create the QApplication.
Why not create the QApplication where you create the GUI object, just before it?
Upvotes: 3