Reputation: 612
How can I select a random element from a character array in c ?
For instance:
char *array[19];
array[0] = "Hi";
array[1] = "Hello";
etc
I am looking for something like array[rand], where rand is the random integer number between o and the array's length(in this case 20) like 1, 2, 3 , 19 etc.
Upvotes: 2
Views: 39587
Reputation: 11
This can be done using rand in the c library stdlib.h
You can get a random number like this:
char random_elem = array[rand()%20];
and you can print it out like this:
printf("%d",array[rand()%20]);
Upvotes: 0
Reputation: 1121
To start things off, since you have an array of strings, not of characters, you have to declare it as char* array[19];
Then, you can declare the following (always useful) macro
#define ARR_SIZE(arr) ( sizeof((arr)) / sizeof((arr[0])) )
Last, you can choose arr[rand() % ARR_SIZE(arr)]
(while keeping in mind that performing %
on rand()
is not the proper way to do get a random number within a range.
Upvotes: 3
Reputation: 2179
You can try array[rand() % ARRAY_LEN] but you are going to get a single char and not a char*
and when you are doing array[0] = "Hi"; it's not correct since you are assigning to a single char
a char*
or turn your char array[20]
into a char *array[20]
and you can assign a string of characters
Upvotes: 2
Reputation: 70929
What you propose is the best solution there is - choose a random index and then use the element at this index. If your question is how to get a random integer, use the built-in function rand()
.
Upvotes: 0