Formatting Time as %d-%m-%y

Question

am trying to print orig_time as 6/9/2013 and running into following error..can anyone provide inputs on what is wrong here

Code:

orig_time="2013-06-09 00:00:00"
Time=(orig_time.strftime('%m-%d-%Y'))
print Time

Error:-

Traceback (most recent call last):
  File "date.py", line 2, in <module>
    Time=(orig_time.strftime('%m-%d-%Y'))
AttributeError: 'str' object has no attribute 'strftime'

Answer 1

import time

now1 = time.strftime("%d-%m-%y", time.localtime())
print(now1)

If you'd prefer, you can change the "d-m-y" as you want and can use a static time.

Answer 2

import time

orig_time="2013-06-09 00:00:00" 

Time= time.strftime(orig_time, '%m-%d-%Y')

print Time

Answer 3

You cannot use strftime on a string as it is not a method of string, one way to do this is by using the datetime module:

>>> from datetime import datetime
>>> orig_time="2013-06-09 00:00:00"
#d is a datetime object    
>>> d = datetime.strptime(orig_time, '%Y-%m-%d %H:%M:%S')

Now you can use either string formatting:

>>> "{}/{}/{}".format(d.month,d.day,d.year)
'6/9/2013'

or datetime.datetime.strftime:

>>> d.strftime('%m-%d-%Y')
'06-09-2013'

Answer 4

>>> import time
>>> time.strftime("%m-%d-%y",time.strptime("2013-06-09 00:00:00","%Y-%m-%d %H:%M:%S"))
'06-09-13'

but its more of a pain to remove leading zeros ... If you need that use the other answer

also its unclear what you want, since your title says one thing (and your format string), but it does not match what you say is your expected output in the question