JW.
JW.

Reputation: 51678

Get multibyte character count before match with preg_match() (PREG_OFFSET_CAPTURE parameter is unhelpfully counting bytes)

I'm trying to search a UTF8-encoded string using preg_match.

preg_match('/H/u', "\xC2\xA1Hola!", $a_matches, PREG_OFFSET_CAPTURE);
echo $a_matches[0][1];

This should print 1, since "H" is at index 1 in the string "¡Hola!". But it prints 2. So it seems like it's not treating the subject as a UTF8-encoded string, even though I'm passing the "u" modifier in the regular expression.

I have the following settings in my php.ini, and other UTF8 functions are working:

mbstring.func_overload = 7
mbstring.language = Neutral
mbstring.internal_encoding = UTF-8
mbstring.http_input = pass
mbstring.http_output = pass
mbstring.encoding_translation = Off

Any ideas?

Upvotes: 48

Views: 79163

Answers (10)

Guy Fawkes
Guy Fawkes

Reputation: 2441

Code below can work both as replacement for preg_match and preg_match_all functions and returns correct matches with correct offset for UTF8-encoded strings.

mb_internal_encoding('UTF-8');

/**
 * Returns array of matches in same format as preg_match or preg_match_all
 * @param bool   $matchAll If true, execute preg_match_all, otherwise preg_match
 * @param string $pattern  The pattern to search for, as a string.
 * @param string $subject  The input string.
 * @param int    $offset   The place from which to start the search (in bytes).
 * @return array
 */
function pregMatchCapture($matchAll, $pattern, $subject, $offset = 0)
{
    $matchInfo = array();
    $method    = 'preg_match';
    $flag      = PREG_OFFSET_CAPTURE;
    if ($matchAll) {
        $method .= '_all';
    }
    $n = $method($pattern, $subject, $matchInfo, $flag, $offset);
    $result = array();
    if ($n !== 0 && !empty($matchInfo)) {
        if (!$matchAll) {
            $matchInfo = array($matchInfo);
        }
        foreach ($matchInfo as $matches) {
            $positions = array();
            foreach ($matches as $match) {
                $matchedText   = $match[0];
                $matchedLength = $match[1];
                $positions[]   = array(
                    $matchedText,
                    mb_strlen(mb_strcut($subject, 0, $matchedLength))
                );
            }
            $result[] = $positions;
        }
        if (!$matchAll) {
            $result = $result[0];
        }
    }
    return $result;
}

$s1 = 'Попробуем русскую строку для теста';
$s2 = 'Try english string for test';

var_dump(pregMatchCapture(true, '/обу/', $s1));
var_dump(pregMatchCapture(false, '/обу/', $s1));

var_dump(pregMatchCapture(true, '/lish/', $s2));
var_dump(pregMatchCapture(false, '/lish/', $s2));

Output of my example:

array(1) {
  [0]=>
  array(1) {
    [0]=>
    array(2) {
      [0]=>
      string(6) "обу"
      [1]=>
      int(4)
    }
  }
}
array(1) {
  [0]=>
  array(2) {
    [0]=>
    string(6) "обу"
    [1]=>
    int(4)
  }
}
array(1) {
  [0]=>
  array(1) {
    [0]=>
    array(2) {
      [0]=>
      string(4) "lish"
      [1]=>
      int(7)
    }
  }
}
array(1) {
  [0]=>
  array(2) {
    [0]=>
    string(4) "lish"
    [1]=>
    int(7)
  }
}

Upvotes: 9

mickmackusa
mickmackusa

Reputation: 48091

I think working with PREG_OFFSET_CAPTURE in this case only creates more work.

Demo of below scripts.

If the pattern only contains literal characters, then preg_ is overkill, just use mb_strpos() and bear in mind that the returned value will be false if the needle is not found in the haystack.

var_export(mb_strpos($str, 'H')); // 1

If you know that the needle will exist in the haystack, you can use preg_match_all() with the marvellous \G (continue) metacharacter and \X (multibyte any character) metacharacter.

echo preg_match_all('/\G(?![A-Z])\X/u', $str); // 1
// if needle not found, will return the mb length of haystack

If you don't know if the needle will exist in the haystack, just check if the returned count is equal to the multibyte length of the input string.

$mbLength = preg_match_all('/\G(?![A-Z])\X/u', $str, $m);
var_export(mb_strlen($str) !== $mbLength ? $mbLength : 'not found');

But if you are going to call an extra mb_ function anyhow, then make just one match, check if a match was made, and measure its multibyte length if so.

var_export(
    preg_match('/\X*?(?=[A-Z])/u', $str, $m) ? mb_strlen($m[0]) : 'not found' 
);

All this said, I've never seen the need to count the multibyte position of something unless the greater task was to isolate or replace a substring. If this is the case, avoid this step entirely and just use preg_match() or preg_replace() to more directly serve your needs.

Upvotes: 0

Mike
Mike

Reputation: 422

The problem was solved to me just by using casual substr instead of expected mb_substr (PHP 7.4).

The mb_substr together with preg_match_all / PREG_OFFSET_CAPTURE (despite using or not using /u modifier)resulted in incorrect position when text contained euro sign symbol (€).

Also iconv and utf8_encode did not help, and I was not able to use htmlentities.

Just reverting to simple substr helped, and it worked with € and other characters correctly.

Upvotes: 0

fracz
fracz

Reputation: 21278

You can calculate the real UTF-8 offset by cutting the string to the offset returned by the preg_mach with the byte-counting substr and then measuring this prefix with the correct-counting mb_strlen.

$utf8Offset = mb_strlen(substr($text, 0, $offsetFromPregMatch), 'UTF-8');

Upvotes: 3

Natxet
Natxet

Reputation: 297

Try adding this (*UTF8) before the regex:

preg_match('(*UTF8)/H/u', "\xC2\xA1Hola!", $a_matches, PREG_OFFSET_CAPTURE);

Magic, thanks to a comment in https://www.php.net/manual/function.preg-match.php#95828

Upvotes: 28

Danon
Danon

Reputation: 2983

You might want to look at T-Regx library.

pattern('/Hola/u')->match('\xC2\xA1Hola!')->first(function (Match $match) 
{
    echo $match->offset();     // characters
    echo $match->byteOffset(); // bytes
});

This $match->offset() is UTF-8 safe offset.

Upvotes: 1

bronek89
bronek89

Reputation: 34

I wrote small class to convert offsets returned by preg_match to proper utf offsets:

final class NonUtfToUtfOffset
{
    /** @var int[] */
    private $utfMap = [];

    public function __construct(string $content)
    {
        $contentLength = mb_strlen($content);

        for ($offset = 0; $offset < $contentLength; $offset ++) {
            $char = mb_substr($content, $offset, 1);
            $nonUtfLength = strlen($char);

            for ($charOffset = 0; $charOffset < $nonUtfLength; $charOffset ++) {
                $this->utfMap[] = $offset;
            }
        }
    }

    public function convertOffset(int $nonUtfOffset): int
    {
        return $this->utfMap[$nonUtfOffset];
    }
}

You can use it like that:

$content = 'aą bać d';
$offsetConverter = new NonUtfToUtfOffset($content);

preg_match_all('#(bać)#ui', $content, $m, PREG_OFFSET_CAPTURE);

foreach ($m[1] as [$word, $offset]) {
    echo "bad: " . mb_substr($content, $offset, mb_strlen($word))."\n";
    echo "good: " . mb_substr($content, $offsetConverter->convertOffset($offset), mb_strlen($word))."\n";
}

https://3v4l.org/8Y32J

Upvotes: 1

user187291
user187291

Reputation: 53960

Looks like this is a "feature", see http://bugs.php.net/bug.php?id=37391

'u' switch only makes sense for pcre, PHP itself is unaware of it.

From PHP's point of view, strings are byte sequences and returning byte offset seems logical (i don't say "correct").

Upvotes: 24

Gumbo
Gumbo

Reputation: 655825

Although the u modifier makes both the pattern and subject be interpreted as UTF-8, the captured offsets are still counted in bytes.

You can use mb_strlen to get the length in UTF-8 characters rather than bytes:

$str = "\xC2\xA1Hola!";
preg_match('/H/u', $str, $a_matches, PREG_OFFSET_CAPTURE);
echo mb_strlen(substr($str, 0, $a_matches[0][1]));

Upvotes: 52

velcrow
velcrow

Reputation: 6516

If all you want to do is find the multi-byte safe position of H try mb_strpos()

mb_internal_encoding('UTF-8');
$str = "\xC2\xA1Hola!";
$pos = mb_strpos($str, 'H');
echo $str."\n";
echo $pos."\n";
echo mb_substr($str,$pos,1)."\n";

Output:

¡Hola!
1
H

Upvotes: 1

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