CODEWITHSUNDEEP
timeoutracket
So8res
So8res

Reputation: 10386

Racket run thread for fixed amount of time

I'd like to run an expression in racket speculatively, hoping for (but not particularly expecting) a result. My code has a hard time limit. Is there an easy way to run some racket code for a few seconds, then reliably kill it and execute fallback code before the deadline hits?

Upvotes: 5

Views: 535

Answers (2)

Greg Hendershott
Greg Hendershott

Reputation: 16260

You can create a "worker" thread to do the work, and another "watcher" thread to kill the worker.

This is described in the More: Systems Programming section of the docs.

The simplest, first cut may be sufficient for your calculation:

(define (accept-and-handle listener)
  (define-values (in out) (tcp-accept listener))
  (define t (thread
              (lambda ()
                (handle in out)
                (close-input-port in)
                (close-output-port out))))
  ; Watcher thread:
  (thread (lambda ()
            (sleep 10)
            (kill-thread t))))

However if you're dealing with other resources read on to learn about custodians.

Upvotes: 3

Asumu Takikawa
Asumu Takikawa

Reputation: 8523

Yes, an easy way to do this is using the engine library. For example:

#lang racket

(require racket/engine)

(define e (engine
           (λ (_)
             ;; just keep printing every second
             (let loop ()
               (displayln "hi")
               (sleep 1)
               (loop)))))

;; run only for 2 seconds
(engine-run 2000 e)

Instead of specifying a time, you can also specify an event object so that the thread stops running when the event triggers.

Upvotes: 6

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