Reputation:
I have this code:
import sys
def random(size=16):
return open(r"C:\Users\ravishankarv\Documents\Python\key.txt").read(size)
def main():
key = random(13)
print(key)
When I try running the script, there are no errors, but nothing appears to happen. I expected it to print some content from the key file, but nothing is printed.
What is wrong? How do I make the code run?
Upvotes: 18
Views: 55783
Reputation:
You've not called your main function at all, so the Python interpreter won't call it for you.
Add this as the last line to just have it called at all times:
main()
Or, if you use the commonly seen:
if __name__ == "__main__":
main()
It will make sure your main method is called only if that module is executed as the starting code by the Python interpreter. More about that here: What does if __name__ == "__main__": do?
If you want to know how to write a 'main' function, Guido van Rossum (the creator of Python) wrote about it in 2003.
Upvotes: 37
Reputation: 61625
Python runs scripts from top to bottom. def
is a statement, and it executes when it is encountered, just like any other statement. However, the effect of this is to create the function (and assign it a name), not to call it. Similarly, import
is a statement that loads the other module (and makes its code run top to bottom, with its own global-variable context), and assigns it a name.
When the example code runs, therefore, three things happen:
The code for the sys
standard library module runs, and then the name sys
in our own module's global variables is bound to that module
A function is created from the code for random
, and then the name random
is bound to that function
A function is created from the code for main
, and then the name main
is bound to that function
There is nothing to call the functions, so they aren't called. Since they aren't called, the code inside them isn't run - it's only used to create the functions. Since that code doesn't run, the file isn't read and nothing is print
ed.
Unlike in some other languages, Python does not care that a function is named main
, or anything else. It will not be run automatically.
As the Zen of Python says, "Explicit is better than implicit". If we want a function to be called, we have to call it. The only things that run automatically are the things at top level, because those are the instructions we explicitly gave.
In many real-world scripts, you may see a line that says if __name__ == '__main__':
. This is not "where the script starts". The script runs top to bottom.
Please read What does if __name__ == "__main__": do? to understand the purpose of such an if
statement (short version: it makes sure that part of your top-level code is skipped if someone else import
s this file as a module). It is not mandatory, and it does not have any kind of special "signalling" purpose to say where the code starts running. It is just a perfectly normal if
statement, that is checking a slightly unusual condition. Nothing requires you to use it in a script (aside from wanting to check what it checks), and nothing prevents you from using it more than once. Nothing prevents you from checking whether __name__
is equal to other values, either (it's just... almost certainly useless).
Upvotes: 6
Reputation: 2900
There's no such main
method in python, what you have to do is:
if __name__ == '__main__':
main()
Upvotes: 3
Reputation: 251488
You're not calling the function. Put main()
at the bottom of your code.
Upvotes: 0
Reputation: 60014
Python isn't like other languages where it automatically calls the main()
function. All you have done is defined your function.
You have to manually call your main function:
main()
Also, you may commonly see this in some code:
if __name__ == '__main__':
main()
Upvotes: 13