CODEWITHSUNDEEP
shellunixtr
Mayank Jain
Mayank Jain

Reputation: 2564

Replacing char with single quote using tr in shell scripting

I want to replace new line char(\n) with ',' (along with starting and closing single quotes) in shell script by using tr command. But tr command is not replacing char correctly

Here is the command i used:

< 1.txt tr "\n" "','"

Output for this command :

erer'erer.'erer'erer'

File 1.txt is like :

erer
erer.
erer
erer

Please suggest me how this can be done using the same command.

Question Edited

Upvotes: 2

Views: 10107

Answers (2)

Stephane Chazelas
Stephane Chazelas

Reputation: 6239

tr is only to transliterate characters. You could do:

$ seq 10 | sed "s/.*/'&'/" | paste -sd, -
'1','2','3','4','5','6','7','8','9','10'

Or if you don't want the first and last ':

$ seq 10 | sed '$!G;$!G' | paste -sd "','" -
1','2','3','4','5','6','7','8','9','10

Upvotes: 2

anubhava
anubhava

Reputation: 785611

tr is not the right tool for this since tr does char by char translation instead of char to a string replacement. use awk:

awk '{printf("'"'"'%s'"'"',", $0)} END{print ""}' 1.txt

To avoid all weird double quote/single quote stuff use:

awk '{printf("\x27%s\x27,", $0)} END{print ""}' 1.txt

To avoid printing comma after last line:

awk '{a[cnt++]=$0} END{ for (i=0; i<length(a)-1; i++) printf("\x27%s\x27,", a[i]); 
      print a[i]}' 1.txt

Upvotes: 3

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