Reputation: 1425
I am tring to print out a load of lines in a few loops and I want to find a way of printing out the lines without using \n
as that adds an empty line after each loop is completed. A sample of the code i have is as follows:
def compose_line6(self, pointers, pointers_synset_type):
self.line6 = ''
for A, B in zip(pointers, pointers_synset_type):
self.line6 += 'http://www.example.org/lexicon#'+A+' http://www.monnetproject.eu/lemon#pos '+B+'\n'
return self.line6
def compose_line7(self, pointers, pointer_source_target):
self.line7 = ''
for A, B in zip(pointers, pointer_source_target):
self.line7 += 'http://www.example.org/lexicon#'+A+' http://www.monnetproject.eu/lemon#source_target '+B+'\n'
return self.line7
def compose_contents(self, line1, line2, line3, line4, line5, line6, line7):
self.contents = '''\
'''+line1+'''
'''+line2+'''
'''+line3+'''
'''+line4+'''
'''+line5+'''
'''+line6+'''
'''+line7+''''''
return self.contents
def print_lines(self, contents):
print (contents)
When i print these this is what happens:
http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#pos n
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#pos a
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#source_target 0000
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#source_target 0401
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#source_target 0302
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#source_target 0203
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#source_target 0101
And i would like it like this:
http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#pos n
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#pos a
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#source_target 0000
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#source_target 0401
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#source_target 0302
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#source_target 0203
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#source_target 0101
Help would be great thanks
Upvotes: 0
Views: 120
Reputation: 28370
use:
def compose_contents(self, line1, line2, line3, line4, line5, line6, line7):
self.contents = '\n'.join([line1, line2, line3, line4, line5, line6, line7])
return self.contents
and:
print contents,
Note the comma at the end!
Upvotes: 2
Reputation: 1219
You need to close your quotes before you add newlines:
'''\
'''+line1+'''
'''+line2+'''
'''+line3+'''
'''+line4+'''
'''+line5+'''
'''+line6+'''
'''+line7+''''''
You escaped the first newline, but it is still adding 4 spaces behind line1
. Try this:
print("\n".join([line1, line2, line3, line4, line5, line 6, line7]))
Upvotes: 2
Reputation: 1329
In Python 2.x it will be print "Text",
- nothing after comma.
In Python 3.x it will be print("Text", end="")
- just special argument to print()
function.
Upvotes: 1