CODEWITHSUNDEEP
php
lmarcelocc
lmarcelocc

Reputation: 1361

Imap_email - send php variables in message

I'm send an email for a user, i make a query:

$consulta = mysql_query("SELECT * FROM users WHERE email = '$emailDestinatario'");
if($consulta === FALSE) {
(header('Location: http://l2prime.org/index.php?login=success') xor die(mysql_error()));
}    while($row = mysql_fetch_array($consulta))
{
    $username = $row['username'];
}
}

Then i have the $body that's the variable for the body message on email:

$body = '
<html>
<head>
<title>Recuperação de password.</title>
</head>
<body>
<h3>Dear <?php echo $username?>,</h3>
<p>
<b>Some text here.</b>
</p>
</body>
</html>
';

That's <?php echo $username?> doesn't work, the email arrives "Dear ,", no username at all. Could anyone help me in this one?

Thank you in advance.

Best regards, Marcelo

Upvotes: 0

Views: 94

Answers (3)

Alin Florin
Alin Florin

Reputation: 397

You can use <<<EOF:

$body = <<<EOF
Something Something {$var} Something Something
Something Something 
Something Something Something {$var2}
EOF;

P.S. Why is everybody so worried with SQL injection here? He just wants to send an e-mail, not to query a database..

Upvotes: 0

anon
anon

Reputation:

You don't need a <?php again in the script. It should be:

$body = '
<html>
<head>
<title>Recuperação de password.</title>
</head>
<body>
<h3>Dear '. strip_tags($username) .',</h3>
<p>
<b>Some text here.</b>
</p>
</body>
</html>
';

So, if $username = "foo";, it will output: 

Dear foo,

Some text here.

strip_tags function will strip out HTML / PHP tags from a given string. It's safer.

Upvotes: 0

Sharky
Sharky

Reputation: 6274

I think its pretty obvious

$body = '
<html>
<head>
<title>Recuperação de password.</title>
</head>
<body>
<h3>Dear '.$username.',</h3>
<p>
<b>Some text here.</b>
</p>
</body>
</html>
';

also you could have something like this:

$body = '
<html>
<head>
<title>Recuperação de password.</title>
</head>
<body>
<h3>Dear VARIABLE_USERNAME,</h3>
<p>
<b>Some text here.
Regards,
VARIABLE_SITE_NAME
</b>
</p>
</body>
</html>
';

and then you could replace the VARIABLE_USERNAME and VARIABLE_SITE_NAME and other VARIABLE_XXXXXX with appropriate values:

$body = str_replace("VARIABLE_USERNAME",$username,$body);
$body = str_replace("VARIABLE_SITE_NAME",$site_name,$body);

Upvotes: 2

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